WebService的开发模版(Axis2_1.5环境).docx

WebService的开发模版（Axis2 1.5环境）?今天在做apache-cxf-2.2.2整合Spring时候，出现了包版本与JDK1.5包冲突的问题，折腾了不少时间，还是没解决。于是改为Axis2开发，暂时绕过问题，完成任务要紧。?Axis2已经升级到1.5了，下载地址：/ws/axis2/1_5/axis2-1.5-bin.zip/ws/axis2/1_5/axis2-1.5-war.zip?两个包，bin是开发包，war是部署包，实际上，如果只用jar包，两个里面的jar都一样用。?在IDEA环境下，Axis2的开发环境稍微麻烦些，毕竟没CXF或XFire方便。每次写build.xml脚本也挺麻烦的。这次写个项目模版，方便以后使用。?环境：axis2-1.5jdk1.5idea-8.13apache-tomcat-6.0.20ant-1.6以上即可?一、创建项目?使用idea向导创建一个Java项目，项目结构如下图：testaxis2 ├─lib ├─resources │????└─META-INF └─src ????????└─mytest?二、导入axis2的包?解压缩axis2-1.5-bin.zip到一个目录下，然后直接在idea中引入axis2的包即可。也可以讲axis2的包复制到lib下。?三、创建服务?axis2服务的创建过程就是写Java类，不要求有接口，有也不会错。这里创建一个最简单的Service，作为发布对象。?package mytest; /** * 测试Service * * @author leizhimin 2009-8-4 15:46:39 */publicinterface MyService { ????????String doSomething(String taskname); }?package mytest; /** * 测试Service * * @author leizhimin 2009-8-4 15:48:13 */publicclass MyServiceImpl implements MyService { ????????public String doSomething(String taskname) { ????????????????System.out.println(MyServiceImpl is calling doSomething with + taskname + !); ????????????????return taskname + is finished!; ????????} }?四、描述服务?在项目的resources\META-INF文件夹下面，创建services.xml，内容如下：servicename=mywsscope=applicationtargetNamespace=/????????messageReceivers????????????????messageReceivermep=/2004/08/wsdl/in-only???????????????????????????????????????????????? class=org.apache.axis2.rpc.receivers.RPCInOnlyMessageReceiver/????????????????messageReceivermep=/2004/08/wsdl/in-out???????????????????????????????????????????????? class=org.apache.axis2.rpc.receivers.RPCMessageReceiver/????????/messageReceivers????????schemaschemaNamespace=/xsd/????????parametername=ServiceClassmytest.MyServiceImpl/parameter/service?服务名：myws命名空间：服务实现类：mytest.MyServiceImpl?五、编写构建脚本?用Ant编写build.xml，放到项目根文件夹下。?xmlversion=1.0encoding=UTF-8?projectname=ccmwsbasedir=.default=generate.service????????propertyenvironment=env/????????propertyname=AXIS2_HOMEvalue=F:/axis2-1.5/????????propertyname=wsdl.urivalue=./build/myws.wsdl/?????