物流运输概述精要.ppt

Bill of Materials (BOM) FileA Complete Product Description BOM文件包含完整的产品说明、不止罗列 了物料、零件与配件，还罗列了产品生产 的顺序。 输入MRP程序的三个主要来源： BOM文件 主生产计划 库存记录文件 A产品的物料清单（产品结构树） B(4) E(1) D(2) C(2) F(2) D(3) A 例子：圆珠笔产品结构树 园珠笔 笔芯 笔筒 笔油墨 笔芯头 笔芯杆 笔帽 Example of MRP Logic and Product Structure Tree U(2) X(2) W(1) V(3) Y(2) W(2) T Product Structure Tree for Assembly A Lead Times T 1 week U 2 weeks V 2 weeks W 3 weeks X 1 week Y 1week Given the product structure tree for “A” and the lead time and demand information below, provide a materials requirements plan that defines the number of units of each component and when they will be needed 7周内完成100单位产品的MRP The McGraw-Hill Companies, Inc., 2006 * Example of MRP Logic and Product Structure Tree B(4) E(1) D(2) C(2) F(2) D(3) A Product Structure Tree for Assembly A Lead Times A 1 day B 2 days C 1 day D 3 days E 4 days F 1 day Total Unit Demand Day 10 50 A Day 8 20 B (Spares) Day 6 15 D (Spares) Given the product structure tree for “A” and the lead time and demand information below, provide a materials requirements plan that defines the number of units of each component and when they will be needed LT = 1 day First, the number of units of “A” are scheduled backwards to allow for their lead time. So, in the materials requirement plan below, we have to place an order for 50 units of “A” on the 9th day to receive them on day 10. Next, we need to start scheduling the components that make up “A”. In the case of component “B” we need 4 B’s for each A. Since we need 50 A’s, that means 200 B’s. And again, we back the schedule up for the necessary 2 days of lead time. B(4) E(1) D(2) C(2) F(2) D(3) A Spares LT = 2 4x50=200 B(4) E(1) D(2) C(2) F(2) D(3) A Part D: Day 6 Finally, repeating the process for all components, we have the final materials requirements plan: The McGraw-Hill Companies, Inc., 2006 * B(4) E(1) D(2) C(2) F(2) D(3) A 40 + 15 spares Part D: Day 6 Finally, repeating the process for all components, we have the final material