信号与系统课件第二章.ppt

Ch2 Time-Domain Representations for LTI System (LTI系统的时域分析) Ch2.1 Introduction Ch2.2 The Convolution Sum（卷积和） Impulse response （冲激响应） The Convolution Sum （卷积和） Example 2.1. Direct Evaluation of The Convolution Sum. A discrete-time system is given by Ch2.3 Convolution Sum Evaluation Procedure（离散卷积和的计算过程） Convolution Sum Evaluation Procedure（离散卷积和的计算过程） Convolution Sum Evaluation Procedure离散卷积和的计算过程 Example 2.2. (a) The input signal x[k] above the reflected and time-shifted impulse response h[n – k], depicted as a function of k. (b) The product signal w-5[k] used to evaluate y [–5]. (c) The product signal w5[k] used to evaluate y[5]. (d) The product signal w10[k] used to evaluate y[10]. Example 2.2. (b) The product signal w5[k] used to evaluate y [5]. Example 2.2. (c) The product signal w10[k] used to evaluate y [10]. Example 2.3. Moving-Average Systems. Example 2.3. Convolution Sum Evaluation （离散卷积和的计算） Convolution Sum Evaluation （离散卷积和的计算） Example 2.5. Investment Computation. Problem： Evaluate the discrete-time convolution sums. Ch2.4 Convolution Integral（卷积积分） Convolution Integral（卷积积分） Ch2.5 Convolution Integral Evaluation Procedure连续卷积积分的计算过程 Convolution Sum Evaluation Procedure（连续卷积积分的计算过程） Example 2.6 Example 2.6 Example 2.7 Example 2.7 Ch2.6 Interconnection of LTI systems （LTI系统的互联） Ch2.6 Interconnection of LTI systems （LTI系统的互联） Interconnection of LTI systems （LTI系统的互联） Interconnection of LTI systems （LTI系统的互联） Interconnection of LTI systems （LTI系统的互联） Ch2.7 Properties of the Impulse Response Representations for LTI systems（用冲激响应表示LTI系统的特性） Causal System(因果系统) Stable System(稳定系统) Stable System(稳定系统) Invertible System(可逆系统) Ch2.8 Step Response(阶跃响应) Step Response(阶跃响应) Homework Page 185: 2.46 2.47(a,b) 2.50(a,b,e,g) 复习Ch2.6-2.8，预习Ch2.9-2.11 Ch2.9?? Differential and Difference Equation Representations of LTI Systems（连续LTI系统的微分方程描述,离散LTI系统的差分方程描述） Differential and Difference Equation Representations of LTI Systems（连续LTI系统的微分方程描