计算传热学第3节-第2章 一维导热.ppt

Sun Jining 2008 @ BUAA * Δx=0.6m 2 一维导热 一维导热基本问题 一维稳态导热 T=3℃ T=5℃ P1 Pa Pb Δx=0.6m Δx=0.6m Δx=0.6m Δx=0.6m P2 P3 P4 P5 P2 33.3TP2=16.7TP3+16.7TP1+6 50TP1 =16.7TP2+33.3TPa+6 P3 P5 50TP5=33.3TPb+16.7TP4+6 33.3TP3=16.7TP4+16.7TP2+6 P4 33.3TP4=16.7TP5+16.7TP3+6 Pa Pb TPa =3 TPb =5 TP1 =0.334TP2+2.118 TP2 =0.602TP3+1.49 33.3TP3=16.7TP4+16.7(0.602TP3+1.49) +6 TP3 =(16.7TP4+16.7*1.49+6)/(33.3-16.7*0.602) P1 TP3 =0.718TP4+1.328 Sun Jining 2008 @ BUAA * Δx=0.6m 2 一维导热 一维导热基本问题 一维稳态导热 T=3℃ T=5℃ P1 Pa Pb Δx=0.6m Δx=0.6m Δx=0.6m Δx=0.6m P2 P3 P4 P5 P2 33.3TP2=16.7TP3+16.7TP1+6 50TP1 =16.7TP2+33.3TPa+6 P3 P5 50TP5=33.3TPb+16.7TP4+6 33.3TP3=16.7TP4+16.7TP2+6 P4 33.3TP4=16.7TP5+16.7TP3+6 Pa Pb TPa =3 TPb =5 TP1 =0.334TP2+2.118 TP2 =0.602TP3+1.49 TP3 =0.718TP4+1.328 33.3TP4 =16.7TP5+16.7(0.718TP4+1.328)+6 TP4 =(16.7TP5+16.7*1.328+6)/(33.3-16.7*0.718) P1 TP4 =0.784TP5+1.322 Sun Jining 2008 @ BUAA * Δx=0.6m 2 一维导热 一维导热基本问题 一维稳态导热 T=3℃ T=5℃ P1 Pa Pb Δx=0.6m Δx=0.6m Δx=0.6m Δx=0.6m P2 P3 P4 P5 P2 33.3TP2=16.7TP3+16.7TP1+6 50TP1 =16.7TP2+33.3TPa+6 P3 P5 50TP5=33.3TPb+16.7TP4+6 33.3TP3=16.7TP4+16.7TP2+6 P4 33.3TP4=16.7TP5+16.7TP3+6 Pa Pb TPa =3 TPb =5 TP1 =0.334TP2+2.118 TP2 =0.602TP3+1.49 TP3 =0.718TP4+1.328 TP4 =0.784TP5+1.322 50TP5=33.3*5+16.7(0.784TP5+1.322)+6 TP5 =(33.3*5+16.7*1.322+6)/(50-16.7*0.784) P1 TP5 =5.27 Sun Jining 2008 @ BUAA * TP4 =0.784TP5+1.322 Δx=0.6m 2 一维导热 一维导热基本问题 一维稳态导热 T=3℃ T=5℃ P1 Pa Pb Δx=0.6m Δx=0.6m Δx=0.6m Δx=0.6m P2 P3 P4 P5 P2 33.3TP2=16.7TP3+16.7TP1+6 50TP1 =16.7TP2+33.3TPa+6 P3 P5 50TP5=33.3TPb+16.7TP4+6 33.3TP3=16.7TP4+16.7TP2+6 P4 33.3TP4=16.7TP5+16.7TP3+6 Pa Pb TPa =3 TPb =5 TP1 =0.334TP2+2.118 TP2 =0.602TP3+1.49 TP3 =0.718TP4+1.328 TP4 =0.784*5.27+1.322=5.45 TP5 =5.27 P1 Sun Jining 2008 @ BUAA * Δx=0.6m 2 一维导热 一维导热基本问题 一维稳态导热 T=3℃ T=5℃ P1 Pa Pb Δx=0.6m Δx=0.6m Δx=0.6m Δx=0.6m P2 P3 P4 P5 P2 33.3TP2=16.7TP3+16.7TP1+6 50TP1 =16.7TP2+33.3TPa+6 P3 P5 50TP5=33.3TPb+16.7TP4+6 33.3TP3=16.7TP4+16.7TP2+6 P4 33.3TP4=16.7TP5+16.7TP3+6 Pa