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oracl实验内容2(共40题)
Part 1
Write a query to display the current date. Label the column Date.
select to_char(sysdate,year-mon-day) “Date”
from dual
2. The HR department needs a report to display the employee number, last name, salary, and salary increased by 15.5% (expressed as a whole number) for each employee. Label the column New Salary. Place your SQL statement in a text file named lab_03_02.sql.
select employee_id,last_name,salary,salary*1.155 new_salary
from employees
3. Run your query in the file lab_03_02.sql.
4. Modify your query lab_03_02.sql to add a column that subtracts the old salary from the new salary. Label the column Increase. Save the contents of the file as lab_03_04.sql. Run the revised query.
select employee_id,last_name,salary,salary*1.155 new_salary,salary*0.155 increase
from employees
……
Write a query that displays the last name (with the first letter uppercase and all other letters lowercase) and the length of the last name for all employees whose name starts with the letters J, A, or M. Give each column an appropriate label. Sort the results by the employees’ last names.
select last_name,length(last_name) length
from employees
where last_name like A% or last_name like J%or last_name like M%
order by last_name
Rewrite the query so that the user is prompted to enter a letter that starts the last name. For example, if the user enters H when prompted for a letter, then the output should show all employees whose last name starts with the letter H.
6. The HR department wants to find the length of employment for each employee. For each employee, display the last name and calculate the number of months between today and the date on which the employee was hired. Label the column MONTHS_WORKED. Order your results by the number of months employed. Round the number of months up to the closest whole number.
Note: Your results will differ.
select last_name,round(months_between(sysdate,hire_date)) MONTHS_WORKED
from employees
order by hire_date desc
7. Create
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