互换性与测量技术基础第四版答案.doc

《互换性与测量技术基础》习题参考解答（第3版） 第二章 光滑圆柱体结合的公差与配合 1. 孔或轴 最大极限尺寸 最小极限尺寸 上偏差 下偏差 公差 尺寸标注 孔: Φ10 9.985 9.970 -0.015 -0.030 0.015 Φ10 孔: Φ18 18.017 18 +0.017 0 0.017 Φ18 孔: Φ30 30.012 29.991 +0.012 -0.009 0.021 Φ30 轴: Φ40 39.95 39.888 -0.050 -0.112 0.062 Φ40 轴: Φ60 60.041 60.011 +0.041 +0.011 0.030 Φ60 轴: Φ85 85 84.978 0 -0.022 0.022 Φ85 2. 1) Xmax = 0.033- (-0.098) = 0.131mm Xmin = 0 - (-0.065) = 0.065mm Tf = | 0.131-0.065 | = 0.066mm 2) Ymax = 0 – 0.060 = -0.060mm Ymin = 0.030 – 0.041 = -0.011mm Tf = | -0.060+0.011 | = 0.049mm 3) Xmax = 0.007- (-0.016) =0.023mm Ymax = -0.018 – 0 = -0.018mm Tf = | 0.023 – (-0.018)| = 0.041mm 4) Xmax = 0.039 - 0.002 = 0.037mm Ymax = 0 – 0.027 = -0.027mm Tf =|0.037 – (-0.027)| = 0.064mm 5) Xmax = 0.074 – (-0.140) = 0.214mm Xmin = 0 - (-0.030) = +0.030mm Tf =| 0.214 – 0.030 | = 0.184mm 6) Xmax =0.009 – (-0.019) = 0.028mm Ymax = -0.021 – 0 = -0.021mm Tf =| 0.028 – (-0.021) | = 0.049mm 3. (1) Φ50 Xmax = 0.089mm Xmin = 0.025mm 基孔制、间隙配合 （2）Φ80 Xmax = 0.250mm Xmin = 0.010mm 基轴制、间隙配合 （3）Φ30 Xmax = 0.019mm Ymax = -0.015mm 基轴制、过渡配合 （4）Φ140 Ymax = -0.126mm Ymin = 0mm 基孔制、过盈配合 （5）Φ180 Xmax = -0.235mm Ymin = -0.170mm 基孔制、过盈配合 （6）Φ18 Xmax = 0.004mm Ymax = -0.015mm 基轴制、过渡配合 （7）Φ50 Xmax = 0.033mm Ymax = -0.008mm 基孔制、过渡配合 （8）Φ100 Xmax = 0.032mm Ymax = -0.025mm 基孔制、过渡配合 （9）Φ30 Xmax = 0.006mm Ymax = -0.028mm 基孔制、过渡配合 （10）Φ50 Xmax = 0.023mm Ymax = -0.018mm 基轴制、过渡配合 4. (1) Φ60 (2) Φ30 (3) Φ50 (4) Φ30 (5) Φ50 5. ∵ Xmin = 0.025mm, Xmax = 0.066mm . ∴配合公差Tf =| 0.066 –0.025| = 0.041mm ， ∵Tf = Th + Ts ,选基孔制.查表，孔为7级，轴为6级Th =0.025mm Ts = 0.016mm符合要求.∴选Φ40。 验算：Xmax =0.025 – (-0.041) = 0.066mm ; Xmin = 0 – (-0.025) = 0.025mm . 符合题意。 6. 1）∵ Tf =|Xmax-Xmin|=|0.086-0.020|=0.066mm, Tf = Th + Ts ∴查表选Th= Ts =0.033mm. 8级公差。基孔制H8,根据Xmin查表选轴为f8，∴选Φ25。 验算Xmax、Xmin后符合要求。 （2）∵Tf =|Ymax-Ymin|=|0.076-(-0.035)|=0.041mm ,Tf = Th + Ts∴查表选Th为7级，Ts为6级，基孔制H7，根据Ymin查表选轴为u6，∴选Φ41验算Ymax、Ymin后符合要求。 (3) ∵Tf =|Xmax-