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[2013年高三数学第一轮复习讲义
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简单的三角
恒等变换
能运用上述公式进行简单的恒等变换(包括导出积化和差、和差化积、半角公式,但不要求记忆).
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高考的必考内容,常利用其解决三角函数的化简、求值和三角恒等式的证明,也常同三角函数的值域、单调性结合在一起考查三角函数的综合应用.
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证明
化简
求值
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【分析】用诱导公式及逆用两角和差的正、余弦公式,将70°,10°,40°化成与20°有关的角,约分求解.
考点1 三角函数式的化简
化简:
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【解析】
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【评析】三角函数式的化简要遵循“三看”原则.
(1)一看“角”,这是最重要的一环,通过看角之间的差别与联系,把角进行合理的拆分,从而正确使用公式;
(2)二看“函数名称”,看函数名称之间的差异,从而确定使用的公式,常见的有“切化弦”;
(3)三看“结构特征”,分析结构特征,可以帮助我们找到变形的方向,常见的有“遇到公式要通分”等.
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Evaluation only.
Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.
Copyright 2004-2011 Aspose Pty Ltd.
Evaluation only.
Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.
Copyright 2004-2011 Aspose Pty Ltd.
Evaluation only.
Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.
Copyright 2004-2011 Aspose Pty Ltd.
Evaluation only.
Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.
Copyright 2004-2011 Aspose Pty Ltd.
考点2 三角函数式求值
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Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.
Copyright 2004-2011 Aspose Pty Ltd.
Evaluation only.
Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0.
Copyright 2004-2011 Aspose Pty Ltd.
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