[电路分析基础-拉普拉斯变换.ppt

时域电路 例 5Ω 2F 20Ω 10Ω 10Ω 0.5H 50V + - u c + - iL t=0时打开开关 uC(0-)=25V iL(0-)=5A t 0 运算电路 20 0.5s - + + - 1/2s 25/s 2.5 5 IL(s) UC(s) Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. § 4 拉普拉斯变换法分析电路 步骤： 1. 由换路前电路计算uC(0-) , iL(0-) 。 2. 画运算电路模型 3. 应用电路分析方法求象函数。 4. 反变换求原函数。 t = 0时闭合k,求iL，uL。 例1： 200V 30Ω 0.1H 10Ω - u c + 1000μF i L + - uL Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. (2) 画运算电路 200/s 30 0.1s 0.5 10 1000/s 100/s I 1 (s) I 2 (s) 例1：求iL(t),uL(t). 200V 30Ω 0.1H 10Ω - u c + 1000μF i L + - uL Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 200/s 30 0.1s 0.5 10 1000/s 100/s I L (s) I 2 (s) Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. (4)反变换求原函数 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 求UL(s) UL(S) 200/s 30 0.1s 0.5 10 1000/s -50/s I 1 (s) I 2 (s) Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 例2 求冲激响应uc. R C + uc ? is ic