[电路分析讲义4.ppt

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[电路分析讲义4

例 b + + + _ _ _ A C B Z Zl Zl Zl Z Z a c + – A N n a Z/3 Zl Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. (1) 将所有三相电源、负载都化为等值Y—Y接电路; (2) 连接各负载和电源中点,中线上若有阻抗可不计; (3) 画出单相计算电路,求出一相的电压、电流: (4) 根据? 接、Y接时 线量、相量之间的关系,求出原电路的电流电压。 (5) 由对称性,得出其它两相的电压、电流。 对称三相电路的一般计算方法: 一相电路中的电压为Y接时的相电压。 一相电路中的电流为线电流。 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 例1 A B C Z Z Z Zl Zl Zl 已知对称三相电源线电压为380V,Z=6.4+j4.8?, Zl =6.4+j4.8?。 求负载Z的相电压、线电压和电流。 解 + – A + – B N + – C Zl Zl Zl Z Z Z + – A N n a Z Zl 画出一相计算图 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. + – A N n a Z Zl Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 例2 A B C Z Z Z A B C Z Z Z 一对称三相负载分别接成Y和?型。分别求线电流。 解 应用:Y??降压起动。 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 例3 如图对称三相电路,电源线电压为380V,|Z1|=10?,cos?1 =0.6(感性), Z2= –j50?, ZN=1+ j2?。 求:线电流、相电流,并定性画出相量图(以A相为例)。 + _ _ _ + + N A C B Z1 Z2 ZN N 解 + _ Z1 画出一相计算图 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copy

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