[绝对值不等式.ppt

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2017-01-09 发布于北京
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[绝对值不等式.ppt

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[绝对值不等式

Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 2010年广东文科数学 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 考点自测 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 答案:5 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. [考向分析] 不等式选讲是广东高考指定选考内容,也就是必考内容.近几年该考点的考查形式有所变化,填空题、解答题中均有出现,考查求解绝对值不等式的考题,难度不大,多为容易题;考查绝对值不等式的证明和应用的考题,难度较大.这部分内容容易与其它知识结合,是考查学生的基本运算能力与推理论证能力的极好素材. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 知识梳理 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 热点一　含绝对值不等式的解法设函数f(x)＝|2x＋1|－|x－4|. (1)解不等式f(x)2; (2)求函数y＝f(x)的最小值. 聚焦高考突破热点例1 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 【规律方法】　这类不等式的解法是高考的热点. (1)用零点分段法解绝对值不等式的步骤: ①求零点;②划区间、去绝对值号;③分别解去掉绝对值的不等式;④取每个结果的并集,注意在分段时不要遗漏区间的端点值. (2)用图象法,数形结合可以求解含有绝对值的不等式,使得代数问题几何化,既通俗易懂,又简洁直观,是一种较好的方法. Evaluation only. Created with Aspose.Slides for .