ForwardErrorCorrection.pptVIP

  1. 1、本文档共21页,可阅读全部内容。
  2. 2、有哪些信誉好的足球投注网站(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
  3. 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载
  4. 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
  5. 5、该文档为VIP文档,如果想要下载,成为VIP会员后,下载免费。
  6. 6、成为VIP后,下载本文档将扣除1次下载权益。下载后,不支持退款、换文档。如有疑问请联系我们
  7. 7、成为VIP后,您将拥有八大权益,权益包括:VIP文档下载权益、阅读免打扰、文档格式转换、高级专利检索、专属身份标志、高级客服、多端互通、版权登记。
  8. 8、VIP文档为合作方或网友上传,每下载1次, 网站将根据用户上传文档的质量评分、类型等,对文档贡献者给予高额补贴、流量扶持。如果你也想贡献VIP文档。上传文档
查看更多
ForwardErrorCorrection

Forward Error Correction Steven Marx CSC457 12/04/2001 Outline What is FEC? What is FEC? (2) Why FEC? Why FEC? (2) How is this possible? How is this possible? (2) How is this possible? (3) A Problem A Solution A Solution (2) Extension Fields Multiplication and Division Multiplication and Division (2) Multiplication and Division (3) Vandermonde Matrices Swarmcast - a real example Swarmcast (2) Other useful applications Conclusion * * What is FEC? Why do we need it? How does it work? Where is it used? Send k packets Reconstruct n packets Such that we can tolerate k-n losses Called an (n, k) FEC code Alternatives: ARQ (Automatic Repeat reQuest) requires feedback bad for multicast tolerance only suitable for some applications Advantages: sometimes no feedback channel necessary long delay path one-way transmission avoids multicast problems Disadvantages: computationally expensive requires over-transmission An easy example: (n, k) = (2, 3) FEC code transmitting two numbers: a and b Send three packets: 1. a 2. b 3. a + b Could be represented as matrix multiplication To encode: To decode, use subset of rows. More generally: y = Gx, where G is a “generator matrix” G is constructed in such a way that any subset of rows is linearly independent. A “systematic” generator matrix includes the identity matrix. a and b are 8-bit numbers a + b may require more bits loss of precision means loss of data Finite fields: field: we can add, subtract, multiply, and divide as with integers closed over these operations finite: finite number of elements Specific example: “prime field” or “Galois Field” - GF(p) elements 0 to p-1 modulo p arithmetic Problem: with the exception of p = 2, ?log(p)? log(p) bits required requires modulo operations q = pr elements with p prime, r 1 “extension field”, or GF(pr) elements can be considered polynomials of degree r - 1 sum just sum modulo p extra simple with p = 2: exactly r bits needed sums and differences just XORs Exists an α whose powe

文档评论(0)

118books + 关注
实名认证
文档贡献者

该用户很懒,什么也没介绍

1亿VIP精品文档

相关文档