Minitab教材讲述.ppt

页眉 * Stat Basic Statistics 2 Proportions State the Hypotheses and Significance Level H0: PBrand A – PBrand B ? 0 Ha: PBrand A – PBrand B 0 ? = 0.05 Test and CI for Two Proportions Sample X N Sample p 1 145 200 0.725000 2 101 150 0.673333 Difference = p (1) - p (2) Estimate for difference: 0.0516667 95% Lower Bound for difference: -0.0299692 Test for difference = 0 (vs not 0): Z = 1.04 P-Value = 0.149 p-value ?; Fail to reject the Null Hypothesis Conclusion: Proportion of relief for Brand A is not statistically greater than the proportion of relief for Brand B 页眉 * Interpretation: p-value = 0.0249 p-value ?-risk (0.05): Reject H0 Infer Ha: Sufficient evidence that the machine is not mixing fruit to the ratio 4:3:2:1 练习二 Chi-Square Test: a, b, c Expected counts are printed below observed counts Chi-Square contributions are printed below expected counts a b c Total 1 5 8 10 23 7.67 7.67 7.67 0.928 0.014 0.710 2 95 92 90 277 92.33 92.33 92.33 0.077 0.001 0.059 Total 100 100 100 300 Chi-Sq = 1.789, DF = 2, P-Value = 0.409 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 页眉 * 1-Sample t Test Testing mean = null (versus null) Calculating power for mean = null + difference Alpha = 0.05 Assumed standard deviation = 1.2 Sample Target Difference Size Power Actual Power -2.5 4 0.8 0.925944 页眉 * 练习一 Test and CI for One Proportion Test of p = 0.73 vs p 0.73 95% Lower Exact Sample X N Sample p Bound P-Value 1 111 143 0.776224 0.711327 0.124 练习二 Test and CI for One Proportion Tes