童诗白-模拟电子技术基础三版习题答案.pdf

2005 1 1? 2× 3? 4× 5? 6× 1A 2C 3C 4B 5AC UO1≈1.3V UO2 0 UO3≈ 1.3V UO4≈2V UO5≈2.3V UO6≈ 2V UO1 6V UO2 5V PCM 200mW UCE 40V IC 5mA UCE 30V IC≈6.67mA UCE 20V IC 10mA UCE 10V IC 20mA 1 IB = VBB ? UBE Rb = 26μA IC = β IB = 2.6mA 2 UCES UBE 0.7V UCE = VCC ? IC RC = 2V UO = UCE = 2V IC = VCC ? UCES Rc = 2.86mA IB = IC β = 28.6μA Rb = VBB ? UBE IB ≈ 45.4k? T1 T2 T3 1.1 1 A C 1.2 1.3 ui uo 2A u i/V 5 3 O -3 uO/V 3.7 O -3.7 1.4 ui u i/V 10 uo O 3C 4A t t t u o /V 10 O t 1.6 ID (V UD)/R 2.6mA rD≈UT/ID 10? Id Ui/rD≈1mA 1.7 1 1.4V 6.7V 8.7V 14V 2 0.7V 6V 1.8 IZM PZM/UZ 25mA R UZ/IDZ 0.24 1.2k? 1.3V 2 38 1.5 uo u I1/V 3 0.3 O uI2 /V 3 t 0.3 O u O/V t 3.7 1 O t 1.9 1 UI 10V UO UZ 6V UO = RL R + RL ?U I ≈ 3.33V UI 15V UO 5V UI 35V UO UZ 5V 4mA 2 I DZ = (U I ? U Z ) R = 29mA IZM 25mA 1.10 1 S 2 Rmin = (V ? U D ) I Dmax ≈ 233? Rmax = (V ? U D ) I Dmin = 700? 1.11 u I /V 6 3 0 u O1/V 3 0 u O2/V 3 0 t t t 1.12 60 1.13 1.14 ICBO≈32μA β 100 ICBO 10μA 1.01mA 5mA (a) (b) 3 38 1.17 UCES UBE β ? VCC ?U Rb BE = VCC ?U RC BE Rb = β RC β ≥ Rb RC = 100 1.15 T1 T2 T3 T4 T5 e c eBc bbbEe c e cCb PNP NPN NPN PNP PNP Si Si Si Ge Ge 1.16 VBB 0 T uO 12V VBB 1V T I BQ = VBB ? U BEQ Rb = 60 A I CQ = β I BQ = 3mA u O = VCC ? I CQ RC = 9V VBB 3V T I BQ = VBB ? U BEQ Rb = 160 A I CQ = β I BQ = 8mA uO = VCC ? ICQ RC U BE 1.18 uI 0 uO UZ 5V uI 5V uO 0.1V IB = uI ? UBE Rb = 480μA IC = β IB = 24mA U EC = VCC ? I C RC VCC 1.19 a b c d T 1.20 iD = I DSS (1 ? uGS U GS(th) ) 2 uGS iD off 1.21 e T6 b e c NPN Ge uGD UGS 1.22 uDS 15V 1.23 uI 4V T uI 8V T 1.24 a b c uI 12V T d iD iD ?(uGS 4 38 1× a b c d e f g h i 2√ 3× 4× VBB G-S T C2 VCC 1 (VCC ? U BEQ ) I BQ 565 5√ 6× 7× (VCC ? U CEQ ) β I BQ 3 2 ? U o U i -120 RL RC RL ? U o 0.3 1A 2C 3B 4B 1 C DE 2 B 3 ACD 4 ABDE 5C 6 BCE AD 2.1 e b c cbc bec 2.2 a VCC VCC c VBB d VBB Rb 2.3 P2.3 b VCC VCC Rc . Ui R1 R2 R 3 . Uo . Ui R1 (a) . Ui R2 R3 R4 . Uo . Ui (c) 2.4 IBQ 20μA ICQ 2mA UCEQ 6V IBQ 20μA ICQ 2mA UCEQ 3V Rb R4 . Uo (b) . Uo RL (d) 5.3V 2.3V 5 38 2.5 1 × 2 × 3 ×