数据结构课后习题解答树和叉树.docVIP

?? 习题及参考答案 　 第六章 树和二叉树 6.33 int Is_Descendant_C(int u,int v)//在孩子存储结构上判断u是否v的子孙,是则返回1,否则返回0{??if(u==v) return 1;??else??{????if(L[v])??????if (Is_Descendant(u,L[v])) return 1;????if(R[v])??????if (Is_Descendant(u,R[v])) return 1; //这是个递归算法??}??return 0;}//Is_Descendant_C 6.34 int Is_Descendant_P(int u,int v)//在双亲存储结构上判断u是否v的子孙,是则返回1,否则返回0{??for(p=u;p!=vp;p=T[p]);??if(p==v) return 1;??else return 0;}//Is_Descendant_P 6.35 这一题根本不需要写什么算法,见书后注释:两个整数的值是相等的. 6.36 int Bitree_Sim(Bitree B1,Bitree B2)//判断两棵树是否相似的递归算法{??if(!B1!B2) return 1;??else if(B1B2Bitree_Sim(B1-lchild,B2-lchild)Bitree_Sim(B1-rchild,B2-rchild))????return 1;??else return 0;}//Bitree_Sim 6.37 void PreOrder_Nonrecursive(Bitree T)//先序遍历二叉树的非递归算法{??InitStack(S);??Push(S,T); //根指针进栈??while(!StackEmpty(S))??{????while(Gettop(S,p)p)????{??????visit(p-data);??????push(S,p-lchild);????} //向左走到尽头????pop(S,p);????if(!StackEmpty(S))????{???? pop(S,p);???? push(S,p-rchild); //向右一步????}??}//while}//PreOrder_Nonrecursive 6.38 typedef struct {???? ??????????????? BTNode* ptr;???????? ??????????? enum {0,1,2} mark;???????? ????????? } PMType; //有mark域的结点指针类型 void PostOrder_Stack(BiTree T)//后续遍历二叉树的非递归算法,用栈{??PMType a;??InitStack(S); //S的元素为PMType类型??Push (S,{T,0}); //根结点入栈??while(!StackEmpty(S))??{????Pop(S,a);????switch(a.mark)????{??????case 0:????????Push(S,{a.ptr,1}); //修改mark域????????if(a.ptr-lchild) Push(S,{a.ptr-lchild,0}); //访问左子树????????break;??????case 1:????????Push(S,{a.ptr,2}); //修改mark域????????if(a.ptr-rchild) Push(S,{a.ptr-rchild,0}); //访问右子树????????break;??????case 2:????????visit(a.ptr); //访问结点,返回????}??}//while}//PostOrder_Stack分析:为了区分两次过栈的不同处理方式,在堆栈中增加一个mark域,mark=0表示刚刚访问此结点,mark=1表示左子树处理结束返回,mark=2表示右子树处理结束返回.每次根据栈顶元素的mark域值决定做何种动作. 6.39 typedef struct {???????????? ??????? int data;??????????? ???????? EBTNode *lchild;??????????? ???????? EBTNode *rchild;?????????? ????????? EBTNode *parent;?????????? ????????? enum