- 1、本文档共7页,可阅读全部内容。
- 2、有哪些信誉好的足球投注网站(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
- 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载。
- 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
查看更多
Isometries for the Caratheodory Metric
a
r
X
i
v
:
0
7
0
7
.2
3
2
9
v
2
[
m
a
t
h
.F
A
]
1
9
S
e
p
2
0
0
7
ISOMETRIES FOR THE CARATHE?ODORY METRIC
MARCO ABATE AND JEAN-PIERRE VIGUE?
1. Introduction
The following problem has been studied by many authors. Let D1
and D2 be two bounded domains in complex Banach spaces and let
f : D1 → D2 be a holomorphic map such that f
′(a) is a surjective
isometry for the Carathe?odory infinitesimal metric at a point a of D1.
The problem is to know whether f is an analytic isomorphism of D1
onto D2. For example, J.-P. Vigue? [8] proved this is the case when
D1 and D2 are two bounded domains in C
n and D1 is convex. Similar
results have been obtained when D2 is convex using the Kobayashi
infinitesimal metric (I. Graham [3] and L. Belkhchicha [1]). We have to
remark that all these results are based on the theorem of L. Lempert
([5] et [6]; one can also consult M. Jarnicki and P. Pflug [4]) on the
equality of Kobayashi and Carathe?odory metrics on a bounded convex
domain in Cn. J.-P. Vigue? [9] proved the first results on this subject in
the case of bounded domains in complex Banach spaces.
Now, we can study the same problem dropping the hypothesis that
f ′(a) is surjective. So, we only suppose that f ′(a) is an isometry for
the Carathe?odory infinitesimal metric. Does this imply that f(D1) is
a complex analytic closed submanifold of D2 and that f is an analytic
isomorphism of D1 onto f(D1)?
Some results have been obtained by J.-P. Vigue? [10] and P. Mazet
[7] assuming that D1 and D2 are open unit balls in complex Banach
spaces, that a = 0, and that the image of f ′(0) contains enough complex
extremal points of the boundary of D2. Under these hypotheses they
proved that f is linear equal to f ′(0). This result shows that f(D1) is
an analytic submanifold of D2 and that f is an analytic isomorphism
of D1 onto f(D1).
Of course, if we do not suppose the existence of complex extremal
points in the image of f ′(0), the map f has no reason to be linear.
However, one can hope
您可能关注的文档
- helix angle.pdf
- Hello I am Baymax――时下最治愈英语学习(●―●).pdf
- HelpStar Technology for Semi-Autonomous Wheelchairs.pdf
- Hemorheologic events in severe shock 1.pdf
- Henkel Potting material.pdf
- Henkel NVH poster.pdf
- Henry and Mudge tall tree house.pdf
- Hepatocyte growth factor effects on mesenchymal stem cells Proliferation.pdf
- Here we report our approach to the “Pittsburgh Brain Activity Interpretation Competition 2.pdf
- Hertfordshire Village of the Year Competition 2010.pdf
文档评论(0)