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MATH1004_Discrete Math_2012 Semester 2_tut03s
The University of Sydney
MATH 1004
Second Semester Discrete Mathematics 2012
Tutorial 3 Week 4
1. Define f : N → N by f(x) = x+ 1. Determine whether or not f is
(a) one-to-one; (b) onto.
Solution.
(a) If x 6= y, then clearly x + 1 6= y + 1 so that f(x) 6= f(y). Hence f is
one-to-one.
(b) Since x + 1 ≥ 1 for all x ∈ N, we see that there is no x ∈ N such that
f(x) = x+ 1 = 0 and hence f is not onto.
2. Each of the following sets of pairs may or may not represent a function from
{1, 2, 3} to {a, b, c, d}.
{(1, d), (2, b), (3, d)}, {(1, c), (2, a), (3, b)}, {(1, a), (3, b)}
{(1, a), (1, c), (3, d)}, {(2, b), (3, c), (1, d)}
(i) Identify the sets which represent functions and determine which of these
are one-to-one.
(ii) Explain clearly why each of the sets does or does not represent a function.
(iii) Explain clearly why each of the sets does or does not represent a one-to-
one function.
Solution.
(a) The set {(1, d), (2, b), (3, d)} represents a function since each of the ele-
ments 1,2,3 appears exactly once as the first term of an ordered pair. It
is not one-to-one since d appears more than once as the second term of
an ordered pair.
(b) The set {(1, c), (2, a), (3, b)} represents a function since each of the ele-
ments 1,2,3 appears exactly once as the first term of an ordered pair. It
is one-to-one since none of the elements a,b,c,d appear more than once as
second terms of ordered pairs.
(c) The set {(1, a), (3, b)} does not represent a function on the set 1,2,3 since
2 does not appear as the first term of an ordered pair.
(d) The set {(1, a), (1, c), (3, d)} does not represent a function since 1 appears
more than once as the first term of an ordered pair. (Also, 2 does not
appear as the first term of an ordered pair).
2(e) The set {(2, b), (3, c), (1, d)} represents a function since each of 1,2,3 ap-
pears exactly once as the first term of an ordered pair. It is one-to-one
since none of a,b,c,d appear more than once as the second term of an
ordered pair.
3. (i) Let
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