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Universal Kriging
University of California, Los Angeles
Department of Statistics
Statistics C173/C273 Instructor: Nicolas Christou
Universal kriging
The Ordinary Kriging (OK) that was discussed earlier is based on the constant mean model
given by
Z(s) = μ+ δ(s)
where δ(·) has mean zero and variogram 2γ(·). Many times this is a too simple model to use.
The mean can be a function of the coordinates X, Y , in some linear, quadratic, or higher
form. For example the value of Z at location s can be expressed now as
Z(si) = β0 + β1Xi + β2Yi + δ(si), linear
Or
Z(si) = β0 + β1Xi + β2Yi + β3X
2
i + β4XiYi + β5Y
2
i + δ(si), quadratic, etc.
If this is the case then we say that there is a trend of the polynomial type. We need to take
this into account when we find the kriging weights. The predicted value Z(s0) at location
s0 will be again a linear combination of the observed Z(si), i = 1, · · · , n values:
Z?(s0) = w1Z(s1) + w2Z(s2) + · · · + wnZ(sn) =
n∑
i=1
wiZi
where
w1 + w2 + · · · + wn = 1
Suppose now that a trend of the linear form is present. Then the value Z?(s0) can be expressed
as
Z?(s0) =
n∑
i=1
wiZi =
n∑
i=1
wiβ0 +
n∑
i=1
wiβ1Xi +
n∑
i=1
wiβ2Yi +
n∑
i=1
wiδ(si)
or
Z?(s0) =
n∑
i=1
wiZi = β0 + β1
n∑
i=1
wiXi + β2
n∑
i=1
wiYi +
n∑
i=1
wiδ(si) (1)
But also the value of Z(s0) can be expressed (based on the linear trend) as
Z(s0) = β0 + β1X0 + β2Y0 + δ(s0) (2)
Compare (1) and (2). In order to ensure that we have an unbiased estimator we will need
the following conditions:
1
n∑
i=1
wiXi = X0
n∑
i=1
wiYi = Y0
and
n∑
i=1
wi = 1
As with ordinary kriging, to find the weights when a trend is present we need to minimize
the mean square error (MSE)
min
(
Z(s0) ?
n∑
i=1
wiZ(si)
)2
subject to the above constraints. This minimization will be unconstrained if we incorporate
the 3 constraints in the objective function. The result is a system of n+ 3 equations for the
linear trend.
If the trend is quadratic we will need n + 6 equations, and n + 10 equations for a three-
dimentional quadratic trend, etc.
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