- 1、本文档共30页,可阅读全部内容。
- 2、有哪些信誉好的足球投注网站(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
- 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载。
- 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
- 5、该文档为VIP文档,如果想要下载,成为VIP会员后,下载免费。
- 6、成为VIP后,下载本文档将扣除1次下载权益。下载后,不支持退款、换文档。如有疑问请联系我们。
- 7、成为VIP后,您将拥有八大权益,权益包括:VIP文档下载权益、阅读免打扰、文档格式转换、高级专利检索、专属身份标志、高级客服、多端互通、版权登记。
- 8、VIP文档为合作方或网友上传,每下载1次, 网站将根据用户上传文档的质量评分、类型等,对文档贡献者给予高额补贴、流量扶持。如果你也想贡献VIP文档。上传文档
查看更多
南昌大学2014上半年度材料热力学重点题(附氧势图)
solution:
Solution:,exothermic reaction
For the reaction :
Solution: (a) When the equilibrium is reached,
T = 500?C = 773K
at T=300?C=573K,
Although the equilibrium PO2 is very low, kinetically the reaction is not favoured and reaction speed is very slow. So 300?C is not suitable at
At T=800?C=1073K, lnPO2 =-22.2, PO2 =2.28?10-10 atm.
At 800?C, if the equilibrium is reached, nitrogen can be of high purity level. However, at this high temperature , particles of Cu will weld together to reduce effective work surface. So it is not suitable to use this high temperature in purification either.
(c ) The equilibrium oxygen pressure remains the same when the total pressure increases, which means a higher purity level of N2 .
Solution: N2 =2N, H2 = 2H
,
For N2 dissolving :
For H2 dissolving:
(a)For dissolving N2, PN2 = 1 atm, [N]=35cm3/100g melt,
similarly: [H]’ =24.75cm3/100g melt
total gas : [H]?+[N]? = 49.5 cm3/100g melt
(b) [H]? =24.75 cm3/100g melt
(c ) [H]?+[N]? = [N](0.33)1/2 /1+[H](0.33)1/2 /1=20.10+20.10 = 40.2cm3/100g melt
Solution:
(1)0.2 (2) (3)
Solution:(a)
(b)
(c)
Solution:(b) (c)
答案更正为:
Temperature Phase Composition Fraction 1300 Liquid 60 61.5 α 8 38.5 β 99 0 1000+ Liquid 70 50.8 α 9 49.2 β 98 0 1000- Liquid _ 0 α 7 63.7 β 98 36.3
Solution:
Solution
Solution:
Solution
Solution:
solution:
Solution:
Solution: (a) At 0?C, ?G =0, ? Tm?S = ?H
(b) At 0?C, ?G =0
? a reversible process can be designed as follows to do the calculation:
(d)
Solution: (a)
(b) No, diamond is not thermodynamically stable relative to graphite at 298K.
(c )
(c ) Assuming N atm , ?G = 0, reversible processes as following can be designed to realize this,
文档评论(0)