CAD获取1个图形上所有直线的交点.docxVIP

 HYPERLINK /thread-95662-1-1.html CAD获取一个图形上所有直线的交点 纯数学运算的方法做的 通过构建二元一次方程 然后 判断相交点是否在线上...代码完全可行哈 using?(var?tr?=?doc.TransactionManager.StartTransaction()) ?{ ??var?lines?=?new?ListLine(); ??foreach(ObjectId?id?in?res.Value.GetObjectIds()) ??{ ????lines.Add((Line)tr.GetObject(id,?OpenMode.ForRead)); ?} ???ListPoint3d?pts?=?new?ListPoint3d(); ?for?(int?m?=?0;?m??lines.Count;?m++) { ???LineSegment3d?ls1?=?new?LineSegment3d(lines[m].StartPoint,?lines[m].EndPoint); ????for?(int?n?=?m?+?1;?n??lines.Count;?n++) ??????{ ?????????LineSegment3d?ls2?=?new?LineSegment3d(lines[n].StartPoint,?lines[n].EndPoint); ???????????CurveCurveIntersector3d?cc3d?=?new?CurveCurveIntersector3d(ls1,?ls2,?Vector3d.ZAxis); ?????????????if?(cc3d.NumberOfIntersectionPoints?==?1) ?????????????????{ ?????????????????????pts.Add(cc3d.GetIntersectionPoint(0)); ????????????????????} ????????} ??} ?BlockTable?bt?=?tr.GetObject(db.BlockTableId,?OpenMode.ForRead)?as?BlockTable; ??BlockTableRecord?btr?=?tr.GetObject(db.CurrentSpaceId,?OpenMode.ForWrite)?as?BlockTableRecord; ??foreach?(var?pt?in?pts) ??{ ????Circle?c?=?new?Circle(pt,?Vector3d.ZAxis,?1); ????????btr.AppendEntity(c); ?????????tr.AddNewlyCreatedDBObject(c,?true); ?????} ????tr.Commit(); } ?} 另一个可行切简洁的代码 ?[CommandMethod(tx1)] public?static?void?CrossCAD() { var?doc?=?Application.DocumentManager.MdiActiveDocument; var?db?=?doc.Database; var?ed?=?doc.Editor; var?sf?=?new?SelectionFilter(new?TypedValue[]{?new?TypedValue(0,?line)}); var?res?=?ed.SelectAll(sf); if?(res.Status?!=?PromptStatus.OK)?return; using?(var?tr?=?doc.TransactionManager.StartTransaction()) { ??var?lines?=?new?ListLine(); ??foreach(ObjectId?id?in?res.Value.GetObjectIds()) ??{ ???lines.Add((Line)tr.GetObject(id,?OpenMode.ForRead)); ??} ListPoint3d?pts?=?new?ListPoint3d(); for?(int?m?=?0;?m??lines.Count;?m++) { LineSegment3d?ls1?=?new?LineSegment3d(lines[m].StartPoint,?lines[m].EndPoint); for?(int?n?=?m?+?1;?n??lines.Count;?n++) { LineSegment3d?ls2?=?new?LineSegment3d(lines[