主要讲解如何躲避代码段效验_以DNF实现无敌讲解.doc

实现无敌的办法很有多 他主要有联动多处判断 我们只选一处 Up u%.[7 ?%K`4 k.gN ?函数原型如下 |B,dEx/uU ?w zdxw$E ?004D12F0 55 PUSH EBP lej^gxj/2 ?004D12F1 8BEC MOV EBP,ESP Scf.4~H 0 ?004D12F3 6A FF PUSH -1 ;\1b{- l ?004D12F5 68 51BCAB00 PUSH 0ABBC51 C?bXrG\ ?004D12FA 64:A1MOV EAX,DWORD PTR FS:[0] _%XbxP6rH ?004D1300 50 PUSH EAX Y{`3`PgN ?004D1301 64:8925 0000000MOV DWORD PTR FS:[0],ESP `AB~YX%( ?004D1308 83EC 78 SUB ESP,78 Fo ?004D130B 8B45 0C MOV EAX,DWORD PTR SS:[EBP+C] @^B S# ?004D130E 56 PUSH ESI o$*bm6o ?004D130F 33F6 XOR ESI,ESI OA\vT${5 ?004D1311 3BC6 CMP EAX,ESI +!D=SnBGs ?004D1313 8975 EC MOV DWORD PTR SS:[EBP-14],ESI PEK.Kt\M ?004D1316 0F84JE 004D1684 tj`tLYOZ@- ?004D131C 3975 14 CMP DWORD PTR SS:[EBP+14],ESI n U+pnkMj ?004D131F 0F84 5F030000 JE 004D1684 B:B0p+$I ?004D1325 53 PUSH EBX }(8D!XgWa ?004D1326 8B5D 08 MOV EBX,DWORD PTR SS:[EBP+8] b\lNE!L ?004D1329 8B03 MOV EAX,DWORD PTR DS:[EBX] k8!hvJ)? ?004D132B 57 PUSH EDI s|fCR ?004D132C 8D4D E4 LEA ECX,DWORD PTR SS:[EBP-1C] BYhmJC| ?004D132F 51 PUSH ECX 8#NIs@DJ ?004D1330 8BCB MOV ECX,EBX h08NvalQ ?004D1332 FF90 CC020000 CALL NEAR DWORD PTR DS:[EAX+2CC] m 70`{-O ?004D1338 8BC8 MOV ECX,EAX LZ=wz.u ?004D133A 8975 FC MOV DWORD PTR SS:[EBP-4],ESI s8`}x_k= ?004D133D C745 EC 0100000MOV DWORD PTR SS:[EBP-14],1 \}]=?}( ?004D1344 E8 478C5800 CALL 00A59F90 N2+mN0k; ?004D1349 85C0 TEST EAX,EAX yoq\9* ?u^ ?004D134B 8B7D 10 MOV EDI,DWORD PTR SS:[EBP+10] :8\*)^E ?004D134E 74 2B JE SHORT 004D137B op.PS{_t ?004D1350 8B17 MOV EDX,DWORD PTR DS:[EDI] Plnd)i` ?004D1352 8D45 DC LEA EAX,DWORD PTR SS:[EBP-24] S-N|uR6 ?004D1355 50 PUSH EAX tW Cv]* ?004D1356 8BCF MOV ECX,EDI y4)ZUv,} ?004D1358 FF92 D0020000 CALL NEAR DWORD PTR DS:[EDX+2D0] 82^ z -t{ ?004D135E 8BC8 MOV ECX,EAX 7W+Uq ?004D1360 C745 FC 0100000MOV DWORD PTR SS:[EBP-4],1 n ##w[7B* ?004D1367 C745 EC 0300000MOV DWORD PTR SS:[EBP-14],3 n{qa]3 ?004D136E E8 1D8C5800