网站大量收购闲置独家精品文档,联系QQ:2885784924

第三章Lyapunov指数的非线性控制.ppt

  1. 1、本文档共54页,可阅读全部内容。
  2. 2、有哪些信誉好的足球投注网站(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
  3. 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载
  4. 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
查看更多
Sensitivity on the initial conditions also happens in linear systems SIC leads to chaos only if the trajectories are bounded (the system cannot blow up to infinity). With linear dynamics either SIC or bounded trajectories. With nonlinearities could be both. xn+1= 2xn But this is “explosion process”, not the deterministic chaos! Why? There is no boundness. There is no folding without nonlinearities! The Lyapunov Exponent A quantitative measure of the sensitive dependence on the initial conditions is the Lyapunov exponent ?. It is the averaged rate of divergence (or convergence) of two neighboring trajectories in the phase space. Actually there is a whole spectrum of Lyapunov exponents. Their number is equal to the dimension of the phase space. If one speaks about the Lyapunov exponent, the largest one is meant. x0 p1(0) t - time flow p2(t) p1(t) p2(0) x(t) Definition of Lyapunov Exponents Given a continuous dynamical system in an n-dimensional phase space, we monitor the long-term evolution of an infinitesimal n-sphere of initial conditions. The sphere will become an n-ellipsoid due to the locally deforming nature of the flow. The i-th one-dimensional Lyapunov exponent is then defined as following: On more formal level The Multiplicative Ergodic Theorem of Oseledec states that this limit exists for almost all points x0 and almost all directions of infinitesimal displacement in the same basin of attraction. Order: λ1 λ2 … λn The linear extent of the ellipsoid grows as 2λ1t The area defined by the first 2 principle axes grows as 2(λ1+λ2)t The volume defined by the first 3 principle axes grows as 2(λ1+λ2+λ3)t and so on… The sum of the first j exponents is defined by the long-term exponential growth rate of a j-volume element. Signs of the Lyapunov exponents Any continuous time-dependent DS without a fixed point will have ?1 zero exponents. The sum of the Lyapunov exponents must be negative in dissipative DS ? ? at least one negative Lyapunov exponent

文档评论(0)

junjun37473 + 关注
实名认证
内容提供者

该用户很懒,什么也没介绍

1亿VIP精品文档

相关文档