Spreadsheet Modeling Decision Analysis, 5ed习题答案.pdf

Spreadsheet Modeling Decision Analysis, 5ed Cliff T. Ragsdale Check figures for selected odd problems. Chapter 2 7. Optimal objective value = 10.55 9. Optimal objective value = 125 11. Optimal objective value = 154 13. Optimal objective value = 775 15. Optimal objective value = 32500 17. Optimal objective value = 0.75 19. Optimal objective value = 59300 21. Optimal objective value = 26000 23. Optimal objective value = 3.5 million Chapter 3 3. Maximum profit = $775,000 5. Minimum cost per pound = $0.75 7. Maximum profit = $59,300 9. Maximum profit = $26,000 11. Minimal cost = $3.5 million 13. c. Maximum revenue = $444,000 15. c. Maximum new customers = 113,500 17. b. Maximum return = 10.25% 19. c. Maximum return = $8,898 (or 8.898%) 21. c. Minimum cost = $1,049 (in $1,000s) 23. c. Profit = $1,526,500 25. c. Minimum number of employees = 640 27. c. Maximum steam production = 32,174 pounds per ton 29. c. Minimum transportation cost = $730 31. c. Minimum cost = $44,067.67 33. c. Maximum profit = $1,007,750 35. c. Profit = $669,000 37. c. Maximum profit = $29,100 39. c. Minimum investment = $38,149 41. b. Total Finance Charge = $22,878. 43. Among other things, defer $3,000 in payments in March 45. b. Total Profit = $1,309,900 47. b. Branches 1, 2, 6 8 are efficient Chapter 4 3. c. 4.67 d. 15.33. 5. a. 0 b. The new objective would be unbounded. 6. d. No. h. Every additional ton of concentrate unit shipped from Eustis to Miami would increase costs by $50. 7. c. $225 9. b. The profit per acre of cantaloupes would have to increase by $99.50.