单曲拱坝(国外英文资料).doc

单曲拱坝(国外英文资料) A masonry arch dam located in the U Valley, 55.5m high dam, as a single thick arch dam, top width 5m, bottom width of 16m, the arc length 115.65m, camber ratio of 2.1. First, the basic parameters are entered, and the dam body is generated from the bottom up. The origin of the coordinate system is located on the axis of arch dam! And arch dam foundation in the intersection points of reference projection, X axis pointing right Y axis points downstream, Z vertical axis Unit: length -M, force -KN, acceleration -M/S, density -KN/M3 ! ! FINI /CLEAR, START /FILNAME, ARCHDAM, 1 /PLOPTS, DATE, 0 /TRIAD, LBOT /VIEW, 1,1,1,1 /VUP, 1, Z *AFUN, DEG Z_UP=53 upstream water level! Z_DOWN=0, lower water level! Z_SAND=38 sediment water level DENS_SAND=0.6, sedimentation, sediment, and bulk density ANG_FRI=16 - the internal friction angle of silt deposits LAYER_NUM=8! Define the number of arches *DIM, ELEVATION, ARRAY, LAYER_NUM! Define the height of the arch *DIM, T_ARCH, ARRAY, LAYER_NUM! Define arch thickness *DIM, ARCH_RAD, ARRAY, LAYER_NUM, 2, define the arc radius, upstream and downstream *DIM, RAD_CEN, ARRAY, LAYER_NUM! Define the arc center Y value *DIM, ARCH_ANGLE, ARRAY, LAYER_NUM, 2, define the left and right corners of the arc ELEVATION (1) =55.5,47,39,29,24,19,9,0, arch height H_DAM=ELEVATION (1) -ELEVATION (LAYER_NUM) - dam height T_ARCH (1) =5.00,6.68,8.27,10.25,11.24,12.23,14.22,16.00, arch thickness ARCH_RAD (1,1) =68.00,68.00,68.00,68.00,68.00,68.00,68.00,68.00 outside radius *VOPER, ARCH_RAD (1,2), ARCH_RAD (1,1), SUB, T_ARCH (1) - calculate the inner radius RAD_CEN (1) =68.00,68.00,68.00,68.00,68.00,68.00,68.00,68.00, the center of the circle, the Y coordinate ARCH_ANGLE (1,1), =-47.72, -46.36, -45.06, -43.36, -41.88, -40.38, -37.32, -34.48, left center corner ARCH_ANGLE (1,2) =49.73,47.13,44.68,41.57,40.44,39.29,36.92,35.72, right center corner W_DAM1=-ARCH_RAD (1,1) *SIN (ARCH_ANGLE (1,1)) on the left long string! W_DAM2=ARCH_RAD (1,1) *SIN (ARCH_ANG