C++试题及答案(国外英语资料).docVIP

C++试题及答案(国外英语资料) 1. Title: polynomial 1! +2! +3! +...... +15! Sum of values Stored in variable out #include iostream.h Void, main () { Int, out, I, J, factorial; Out = 0; For (I = 1; I 15; i++) { Factorial = 1; For (J = 1; J I; j++) factorial = factorial * j; Out = out + factorial; } Cout out endl; } 2. Title: seek all prime numbers between 1 and 200, and put the prime number into the variable sum #include iostream.h Int prime (int i) { Int j; For (J = 2; J I; j++) { If (... (I% J)) return 0; } If (J = = I) return j; Else return 0; } Void, main () { Int, I, sum; Sum = 0; For (I = 1; I 200; i++) { Sum = sum + prime (I); } Cout sum endl; } 3. Title: using while loop programming, natural numbers between 1 to 100 odd squares And sum. #include iostream.h Void, main () { Int, I, sum; I = 1; Sum = 0; While (I = 100) { Sum = (I * I); I = I + 2; } Cout sum endl; } 4. Title: to determine whether a number 23437 is a prime number The parameter flag, flag is 1, stands for prime number, 0 represents no) #include iostream.h Int prime (int i) { Int j; For (J = 2; J I; j++) { If (... (I% J)) return 0; } If (J = = I) return j; Else return 0; } Void, main () { Int, I, flag; I = 23437; Flag = prime (I) \i; Cout flag endl; } 5. Title: known a number m (=252), ask you sum of numbers #include iostream.h #include string Using namespace std; Void, main () { String s; Int, len, sum, i; S = 252; Len = s.size (); Sum = 0; For (I = 0; I len; i++) Sum = sum + s[i] -0; / / take a digital character, it is the digital value minus the character0 Cout, the sum of your numbers is: sum endl; } 6. Title: the odd number between 1-100 cumulative order into the N, until its and so on At or greater than 200 #include iostream.h Void, main () { Int, I, sum; I = 1; Sum = 0; While (I = 100) { Sum = sum + i; I = I + 2; If (sum = 200 break); } Cout sum endl; } 7. Title: two numbers to calculate x with the division method, the largest convention y number #includeiostream.h Void, main () { Int, a, B, num1,