0 – 1 integer programming modeling examples - rutgers university.ppt

0 – 1 integer programming modeling examples - rutgers university.ppt

  1. 1、本文档共45页,可阅读全部内容。
  2. 2、有哪些信誉好的足球投注网站(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
  3. 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载
  4. 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
查看更多
Chapter 5 - Integer Programming Chapter Topics Integer Programming (IP) Models Integer Programming Graphical Solution Computer Solution of Integer Programming Problems With Excel and QM for Windows University bookstore expansion project. Not enough space available for both a computer department and a clothing department. Data: 0 – 1 Integer Programming Modeling Examples Capital Budgeting Example (1 of 4) x1 = selection of web site project x2 = selection of warehouse project x3 = selection clothing department project x4 = selection of computer department project x5 = selection of ATM project xi = 1 if project “i” is selected, 0 if project “i” is not selected Maximize Z = $120x1 + $85x2 + $105x3 + $140x4 + $70x5 subject to: 55x1 + 45x2 + 60x3 + 50x4 + 30x5 ? 150 40x1 + 35x2 + 25x3 + 35x4 + 30x5 ? 110 25x1 + 20x2 + 30x4 ? 60 x3 + x4 ? 1 xi = 0 or 1 0 – 1 Integer Programming Modeling Examples Capital Budgeting Example (2 of 4) Exhibit 5.16 0 – 1 Integer Programming Modeling Examples Capital Budgeting Example (3 of 4) Exhibit 5.17 0 – 1 Integer Programming Modeling Examples Capital Budgeting Example (4 of 4) 0 – 1 Integer Programming Modeling Examples Fixed Charge and Facility Example (1 of 4) Which of six farms should be purchased that will meet current production capacity at minimum total cost, including annual fixed costs and shipping costs? Data: yi = 0 if farm i is not selected, and 1 if farm i is selected, i = 1,2,3,4,5,6 xij = potatoes (tons, 1000s) shipped from farm i, i = 1,2,3,4,5,6 to plant j, j = A,B,C. Minimize Z = 18x1A + 15x1B + 12x1C + 13x2A + 10x2B + 17x2C + 16x3A + 14x3B + 18x3C + 19x4A + 15x4b + 16x4C + 17x5A + 19x5B + 12x5C + 14x6A + 16x6B + 12x6C + 405y1 + 390y2 + 450y3 + 368y4 + 520y5 + 465y6 subject to: x1A + x1B + x1C - 11.2y1 0 x2A + x2B + x2C -10.5y2 0 x3A + x3B + x3C - 12.8y3 0

文档评论(0)

wangsux + 关注
实名认证
内容提供者

该用户很懒,什么也没介绍

1亿VIP精品文档

相关文档