网站大量收购独家精品文档,联系QQ:2885784924

变压器电容补偿(Transformer capacitor compensation).doc

变压器电容补偿(Transformer capacitor compensation).doc

  1. 1、本文档共17页,可阅读全部内容。
  2. 2、有哪些信誉好的足球投注网站(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
  3. 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载
  4. 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
查看更多
变压器电容补偿(Transformer capacitor compensation)

变压器电容补偿(Transformer capacitor compensation) Focus on the forum come ask you more blog tribal City entertainment Album Music Classified information In the horizon Tianya literature Tianya wall Login skyline registration Tianya help Search question and answer, I want to ask questions Questions list questions How to calculate the line capacitance compensation? [engineering technology] Reward points, 106 answers, 612 times browse Im a baby, kid 2009-5-6 14:19:28 172.30.211.* Report How to calculate the line capacitance compensation? Answer Quote: Add reference: Log in and print the answer to cancel in Google search how to calculate line capacitance compensation? An answer is being issued. Please hold on...... What you entered will be published automatically after you have successfully logged in. System recommended answer 2009-5-6, 14:19:44, 59.49.180.* Report If it is 500 watts: the capacitor capacity required to shunt 0.1854KVA (the calculation process is too complex to only give the results to you, but it is absolutely correct) Power saving is 0.0092 degrees / hour, *24*360=79.488 degrees If 500KW, the capacitor capacity in parallel 185.4KVA is 9.2 degrees per hour, *24*360=79488 degrees Expand other similar answers (2) hide other similar answers (2) Point big dog 2009-5-6 14:19:46 222.82.14.* Report If it is 500 watts: the capacitor capacity required to shunt 0.1854KVA (the calculation process is too complex to only give the results to you, but it is absolutely correct) Power saving is 0.0092 degrees / hour, *24*360=79.488 degrees If 500KW, the capacitor capacity in parallel 185.4KVA is 9.2 degrees per hour, *24*360=79488 degrees -------------------------------------------------------------------------------- 2009-5-6 14:20:08 125.109.215.* report Nini calf If it is 500 watts: the capacitor capacity required to shunt 0.1854KVA (the calculation process is too complex to only give the results to you, but it is absolutely correct) Power saving is 0.0092 degre

您可能关注的文档

文档评论(0)

jgx3536 + 关注
实名认证
内容提供者

该用户很懒,什么也没介绍

版权声明书
用户编号:6111134150000003

1亿VIP精品文档

相关文档