小动画的实现（Implementation of small animation）.doc

小动画的实现（Implementation of small animation） / * ---------------------------- animation ----------------------------- * / / * name: rolling * / / * ---------------------------- animation ----------------------------- * / # include graphics.h # include dos.h # include alloc.h # include stdlib.h # include conio.h void main () { int drives = detect, fashion; int x = 0, y = 190 - 1, r = 10, num; unsigned int size; char * / * / * father buffer; initgraph ( drives, fashion, ); size = imagesize (0169,20189); / * get tthe size of the circle * / buffer = (char father *) malloc (size); / * remember the location of the circle data * / line (0200640200); setcolor (11); circle (x, y, r); setfillstyle (1.11); floodfill (x, y, 11); getimage (0179,20199, buffer); / * store the data of the circle * / for (num = 0; num 32; num + +) { putimage (x 0, y 0, buffer, xor _ put); / * delete the circle * / x + = 20; putimage (x 0, y 0, buffer, copy _ put); / * draw the circle * / delay (50000); } getch (); / * press any key to return to text mode * / closegraph (); } 银行家 / * note: your choice is c idea * / # include stdio.h # include stdlib.h # include conio.h typedef enum = 0 {false, true = 1} all; int max [5] [3] = {{7,5,3}, {3,2,2}, {9,0,2}, {2,2,2}, {4,3,3}}; int a [5] [3] = {{0,1,0}, {2,0,0}, {3,0,2}, {2,1,1}, {0,0,2}}; int need [5] [3] = {{7,4,3}, {1,2,2}, {6,0,0}, {0,1,1}, {4,3,1}}; int available [3] = {3,3,2}; int work [3]; int temp [3]; / * 存放临时资源 * / int finish [10]; int i; int m, n, j, b; int state signal = 0; int t; prinfdate (void) { int p, r; / * p, r分别为进程和资源的数目 * / printf (proceed max allocation need avalible \ n); for (p = 0; p 5; p + +) { / * 进程循环 * / printf (\ np [% d], p); / * 资源循环 * / for (r = 0; r 3; r + +) { printf (% d, max [p] [r]); } printf (); for (r = 0; r 3; r + +) { printf (% d, allocation [p] [r]); } printf (); for (r = 0; r 3; r + +) { printf (% d, need [p] [r]); } printf (); for (r = 0; r 3; r + +) { printf (% d, available [r]); } } } / * 请