哈工大精密机械基础 大作业.docx

应用C语言实现滚子从动件盘状凸轮的轮廓描绘（哈尔滨工业大学 航天学院英才班 ）滚子从动件的轮廓与从动件运动方程有关系，本文就一种运动方程描绘了滚子从动件的轮廓。若有给定的从动件方程，则需要将代码中从动件的运动方程和方程的一阶导改变。滚子从动件盘状凸轮的几个重要参数：E：从动件的偏心距，R：凸轮的基圆半径，：，J：凸轮的转角S:，从动件运动方程，凸轮的理论轮廓线上的某一点坐标（X,Y）从动件规律：推程：；远休止：；回程：；近休止：编程思想:凸轮的代码用了一个循环，当角度变化的时候S也在变化，然后根据变化的S计算出凸轮的坐标。在平面上建立坐标系，计算出滚子内轮廓和外轮廓的坐标，再将横纵坐标取平均，得到滚子滚动的圆心，然后以滚子半径做圆。滚子半径不能太大。运行结果如下：图一为运行界面，图二为凸轮图形图一图二附：凸轮代码：#includegraphics.h#includestdio.h#includeconio.h#includestdlib.h#includemath.hmain(){ float x[361],y[361]; float x1[361],y1[361]; float x2[361],y2[361]; float n1[361]; float n2[361]; int E=10; int H=50; int j1=90; int j2=90; int j3=90; int j4=90; int r1=1; float s0=38.726; float s[360]; int R,j,m=360,gmode,gdriver,gerror; printf(请输入基圆半径R和滚子半径); printf(R=); scanf(%d,R);printf(\t%d,R); printf(r1=); scanf(%d,r1);printf(\t%d,r1); gdriver=VGA; gmode=VGAHI; initgraph (gdriver,gmode,); setbkcolor(BLACK); line(10,240,630,240);line(320,20,320,450); circle(320,240,R); for(j=0;j=360;j++) { if(j360-j4j=360) { s[j]=0; n1[j]=-E*sin(j*3.141592/j1)+(s0+s[j])*cos(j*3.141592/j1); n2[j]=-E*cos(j*3.141592/j1)-(s0+s[j])*sin(j*3.14159/j1); } if(j360-j3-j4j=360-j4) { s[j]=(H-H/2*(1-cos(3.1415926/j3*j))); n1[j]=(100*(-H/2*3.14159/j3*sin(3.14159/j3*j))-E)*sin(j*3.141592/j1)+(s0+s[j])*cos(j*3.141592/j1); n2[j]=(100*(-H/2*3.14159/j3*sin(3.14159/j3*j))-E)*cos(j*3.141592/j1)-(s0+s[j])*sin(j*3.14159/j1); } if(j360-j4-j3-j2j=360-j3-j4) { s[j]=H; n1[j]=-E*sin(j*3.141592/j1)+(s0+s[j])*cos(j*3.141592/j1); n2[j]=-E*cos(j*3.141592/j1)-(s0+s[j])*sin(j*3.14159/j1); } if(j=0j=360-j4-j3-j2) { s[j]=(H/2*(1-cos(3.1415926/j1*j))); n1[j]=(100*(3.14159*H/j1/2*sin(3.14159/j1*j))-E)*sin(j*3.141592/j1)+(s0+s[j])*cos(j*3.141592/j1); n2[j]=(100*(3.14159*H/j1/2*sin(3.1415