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数字信号实验(Digital signal experiment)
数字信号实验(Digital signal experiment)
% plotted the amplitude frequency characteristic of 8 point DFT
Title ((1a) 8 DFT[x_1 (n) ); xlabel (PI / Omega ); ylabel ( range );
Axis ([0,2,0,1.2*max (ABS (X1k8))]
Subplot (2,2,3); mstem (X1k16);%; plot the amplitude frequency characteristic of the 16 point DFT
Title ((1b) 16 DFT[x_1 (n) ); xlabel (PI / Omega ); ylabel ( range );
Axis ([0,2,0,1.2*max (ABS (X1k16))]
Figure (2)
Subplot (2,2,1); mstem (X2k8);%; plot the amplitude frequency characteristic of the 8 point DFT
Title ((2a) 8 DFT[x_2 (n) ); xlabel (PI / Omega ); ylabel ( range );
Axis ([0,2,0,1.2*max (ABS (X2k8))]
Subplot (2,2,2); mstem (X2k16);%; plot the amplitude frequency characteristic of the 16 point DFT
Title ((2b) 16 DFT[x_2 (n) ); xlabel (PI / Omega ); ylabel ( range );
Axis ([0,2,0,1.2*max (ABS (X2k16))]
Subplot (2,2,3); mstem (X3k8);%; plot the amplitude frequency characteristic of the 8 point DFT
Title ((3a) 8 DFT[x_3 (n) ); xlabel (PI / Omega ); ylabel ( range );
Axis ([0,2,0,1.2*max (ABS (X3k8))]
Subplot (2,2,4); mstem (X3k16);%; plot the amplitude frequency characteristic of the 16 point DFT
Title ((3b) 16 DFT[x_3 (n) ); xlabel (PI / Omega ); ylabel ( range );
Axis ([0,2,0,1.2*max (ABS (X3k16))]
% experiment content (2) periodic sequence spectrum analysis ==================================
N=8; n=0:N-1;%FFT transform interval N=8
X4n=cos (pi*n/4);
X5n=cos (pi*n/4) +cos (pi*n/8);
X4k8=fft (x4n);% calculates the 8 point x4n of DFT
X5k8=fft (x5n);% calculates the 8 point x5n of DFT
N=16; n=0:N-1;%FFT transform interval N=16
X4n=cos (pi*n/4);
X5n=cos (pi*n/4) +cos (pi*n/8);
X4k16=fft (x4n);% calculates the 16 point x4n of DFT
X5k16=fft (x5n);% calculates the 16 point x5n of DFT
Figure (3)
Subplot (2,2,1); mstem (X4k8);%; plot the amplitude frequency characteristic of the 8 point DFT
Title ((4a) 8 DFT[x_4 (n) ); xlabel (PI / Omega ); ylabel ( range );
Axis ([0,2,0,1.2*max (ABS (X4k8))]
Subplot (2,2,3); mstem (X4k16);%; plot the amplitude frequency characteristi
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