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晓通笔试题(Xiao Tong passed written examination questions)
晓通笔试题(Xiao Tong passed written examination questions)
1 intermediate Engineer
1.1 scope of application
1-3 years work experience in network engineer with CCNP or H3CSE certificate
1.2 post requirements
Familiar with routing, switching and other network technology principles and configuration methods, network engineering implementation experience, communication, good expression and sense of responsibility.
1.3 initial examination questions (answer time 30 minutes)
1.3.1 as shown in the network topology, if before the two PC without any communication, and now PC1 to PC2 to start communication, please according to the sequence described after what steps, which use agreement, completed what tasks, including PC1, R1, R2, PC2 operation (only need to describe actions the network layer and data link layer)
Answer: Step 1. The PC1 address gets the gateway address via ARP.
Step two, PC1 sends the packet PC2 to R1 for PC1
Step three R1 encapsulation, find PC2 as the destination address, start to see the routing table, look-up table to the interface, and the interface is two layer encapsulation PPP frame
Step four, R1 creates a link to the R2 through LCP, configuring the successful packet to complete the exchange
Step five may perform user authentication via PAP or CHAP
Step six, R2 for R1, assign address with IPCP, PPP link build up successfully
Send data packet structure step seven R1 PPP |IP head | data
Step eight R2 solution package, check the routing table, found that the destination address is PC2 and the Ethernet interface package, re packing Ethernet |IP head | data
Step nine PC2 receives data, and PC1 and PC2 communications succeed.
If it is PPPOE, the situation may be different.
Why does 1.3.2 OSPF divide the area? What kind of network loops may occur under the network structure of OSPF? Why?
A: OSPF has a backbone area of 0, and an ordinary region must be informed by Region 0 of other common regions LSA, SPF, and routing. Partitioning regions can reduce the scope of
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