精美幻灯片模板-商务-学术-科技-工程-人文-理工均适用.ppt

精美幻灯片模板-商务-学术-科技-工程-人文-理工均适用.ppt

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精美幻灯片模板-商务-学术-科技-工程-人文-理工均适用

Title of Your Topic Title of Your Topic Title of Your Topic Name Your University Your Company Your Lab Others About You Date Subtitle of Topic * Contents Research Problem - Introduction - Research question - Subsidiary questions Literature Review Hypotheses Methodology Trial Table of Contents Bibliography * Research Problem Introduction 2. Dissolve 0.59 g of Ba(NO3)2 in 1 L of water. Adjust the castile soap solution so that 2.4 mL of it will give a permanent lather with 40 mL of solution (b). When adjusted, 2.4 mL of soap solution is equivalent to 220 parts per million of hardness (as CaCO3) for a 40 mL sample. See also Soap solution. Brucke’s reagent (protein precipitation). See Potassium iodide-mercuric iodide. Clarke’s soap solution (estimation of hardness in water).. * Literature Review Boutron — Boudet soap solution 1. Dissolve 200 g of Rochelle salt and 150 g of NaOH in sufficient water to make 1 L of solution. 2. Dissolve 40 g of CuSO4 in enough water to make 1 L of solution. 3. Dissolve 50 g of Fe2(SO4)3 and 200 g of H2SO4 (sp. gr. 1.84) in sufficient water to make 1 L of solution. 4. Dissolve 5 g of KMnO4 in sufficient water to make 1 L of solution. Hypotheses * Hypothesis 1. Dissolve 100 g of pure powdered castile soap in 1 L of 80% ethanol and allow to stand over night Subhypotheses 2. Prepare a solution of CaCl2 by dissolving 0.5 g of CaCO3 in HCl (sp. gr. 1.19), neutralize with NH4OH and make slightly alkaline to litmus, and dilute to 500 mL. One mL is equivalent to 1 mg of CaCO3. * Bibliography Dissolve 200 g of Rochelle salt and 150 g of NaOH in sufficient water to make 1 L of solution. 2. Dissolve 40 g of CuSO4 in enough water to make 1 L of solution. 3. Dissolve 50 g of Fe2(SO4)3 and 200 g of H2SO4 (sp. gr. 1.84) in sufficient water to make 1 L of solution. 4. Dissolve 5 g of KMnO4 in sufficient water to make 1 L of solution. * *

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