燕大机电一体化作业4.doc

Name: 何丽 080101010069 No.: 4 Due Time: 2011.10.10 Affiliation: 08级机电2班 8-1. Derive an equation relating the input , force F , with the output , displacement x , for the systems described by figure 8.25 Answer: (a) (b) 8-3. Derive the relationship between the output , the potential difference across the resistor R of , and the input v for the circuit shown in figure 8.26 which has a resistor in series with a capacitor. Answer: 8-4. Derive the relationship between the output, the potential difference across the resistor R of , and the input v for the series LRC circuit shown in figure 8.27. Answer: 8-4. Derive the relationship between the output, the potential difference across the capacitor C of , and the input v for the circuit shown in figure 8.28. Answer: 9-2. The relationship between the e.m.f. E generated by a thermocouple and the temperature T is given by where a and b are constants. Linearise this equation for an operating point of temperature Answer: The relationship between the e.m.f. E generated by a thermocouple and the temperature T is given by So: At the operating point: m = a + 2bT 9-4.Derive a differential equation relation the input voltage to a d.c. servo motor and the output angular velocity, assuming that motor is armature controlled and equivalent circuit for the motor has an armature with just resistance, its inductance being neglected. Answer: According to the d.c. motor Grcuits we can easily get the following equations when inducement is neglect 9-6. Derive differential equations for a permanent magnet d.c. motor. Answer: On the base of the problem4 we can also get: PPT题目1： Answer： PPT题目2： 某步进电机有80个齿, 采用3相6拍方式驱动, 经丝杠螺母副驱动工作台做直线运动, 丝杠的导程为6mm。求: 1、步进电机的步矩角。 2、当脉冲当量要求为0.01mm时,试设计此传动系统 解： ， ， ， 1、 2、 所以可选，，模数=1.5的齿轮传动副 PPT题目3： 将改造一台C620车床，其纵向丝杠的螺距t=12mm，采用110BF003型步进电动机，步 距α=0.75°，系统规定的纵向步进当量=0.01mm，计算步进电动机与纵向丝杠之间的联接传动比。 解： i为