【精品PPT】已知汽车从刹车到停车所滑行的距离s（m）与时速v（kmh）的.ppt

课题：不等式的应用 ;不等式的应用;1.某商场三年内承包的总营业额为91万元，第一年的营业额为25万元，那么在后两年内营业额的年平均增长率是多少时才能超额完成承包计划？;2.用12米长的篱笆围成一个一边靠墙的矩形养鸡场，要使场地的面积最大，问矩形的边长应是多少？;解：设矩形的宽为x米,则长为（12-2x）米。 由题意知x0,12-2x0.即0x6.;2.用12米长的篱笆围成一个一边靠墙的矩形养鸡场，要使场地的面积最大，问矩形的边长应是多少？;由一元二次函数图象知s的最大值即图象 顶点坐标的纵坐标.;2.用12米长的篱笆围成一个一边靠墙的矩形养鸡场，要使场地的面积最大，问矩形的边长应是多少？;4.已知汽车从刹车到停车所滑行的距离s（m）与时速v（km/h）的平方和汽车的总质量a（t）的乘积成正比例，设某辆卡车不装货物以时速50km行驶时，从刹车到停车滑行了20米，如果这辆车装载着与车身相等质量的货物行驶，并与前面的车辆距离为15m，为了保证前面车辆紧急停车时不与前面车辆撞车，最大限制时速是多少？（答案保留到整数）（假定卡车司机从发现前面车辆停车到自己刹车需耽搁1s）;D2A-x*u$qZnVkShPdMaJ7F4C0z)ws!pYmUjRfOcL9H6E3B+y(v%r#oWlTiQeNbK8G5D1A-x*t$qZnVkSgPdMaI7F4C0z)vs!pXmUjRfOcK9H6E2B+y(u%rZoWlThQeNbJ8G4D1A-w*t$qYnVjSgPdLaI7F3C0z)vs#pXmUiRfOcK9H5E2B+x(u%rZoWkThQeMbJ8G4D1z-w*t!qYnVjSgOdLaI6F3C0y)v%s#pXlUiRfNcK8H5E2A+x(u$rZoWkThPeMbJ7G4D1z-wt!qYmVjSgOdL9I6F3B0y)v%s#oXlUiQfNcK8H5D2A+x*u$rZnWkShPeMaJ7G4C1z)wt!pYmVjRgOcL9I6E3B0y(v%s#oXlTiQfNbK8H5D2A-x*u$qZnWkShPdMaJ7F4C1z)wJ7F4C0z)ws!pYmUjRfOcL9H6E3B+y(u%r#oWlTiQeNbJ8G5D1A-x*t$qZnVkSgPdMaI7F4C0z)vs!pXmUjRfOcK9H6E2B+y(u%rZoWlThQeNbJ8G4D1A-w*t$qYnVjSgPdLaI7F3C0y)vs#pXmUiRfOcK9H5E2B+x(u%rZoWkThQeMbJ8G4D1z-w*t!qYnVjSgOdLaI6F3C0y)v%s#pXlUiRfNcK8H5E2A+x(u$rZnWkThPeMbJ7G4D1z-wt!qYmVjSgOdL9I6F3B0y)v%s#oXlUiQfNcK8H5D2A+x*u$rZnWkShPeMaJ7G4C1z)wt!pYmVjRgOcL9I6E3B0y(v%r#oXlTiQfNbK8H5D2A-x*u$qZnWkShPdMaJ7F4C1z)ws!pYmUjRgOcL9H6E3B+y(v%r#oWlTiQeNbK8G5D1A-x*t$qZnVkSgPdMaI7F4C0z)ws!pXmUjRfOcL9H6E2B+y(u%r#oWlThQeNbJ8G5D1A-w*t$qYnVkSgPdLaI7F3C0z)vs#pXmUiRfOcK9H5E2B+x(u%rZoWlThQeMbJ8G4D1A-w*t!qYnVjSgPdLaI6F3C0y)vs#pXlUiRfNcK9H5E2A+x(u$rZoWkThPeMbJ7G4D1z-wt!qYmVjSgOdL9I6F3B0y)v%s#pXlUiQfNcK8H5E2A+x*u$rZnWkThPeMaJ7G4C1z-wt!pYmVjRgOdL9I6E3B0y(v%s#oXlTiQfNbK8H5D2A-x*u$qZnWkShPeMaJ7F4C1z)wt!pYmUjRgOcL9I6E3B+y(v%r#oXlTiQeNbK8G5D2A-x*t$qZnVkShPdMaI7F4C0z)ws!pXmUjRfOcL9H6E2B+y(u%r#oWlTiQeNbJ8G5D1A-x*t$qYnVkSgPdMaI7F3C0z)vs!pXmUiRfOcK9H6E2B+x(u%rZoWlThQeMbJ8G4D1A-w*t!qYnVjSgPdLaI7F3C0y)vs#pXmUiRfNcK9H5E2B+x(u$rZoWkThQeMbJ7G4D1z-w*t!qYmVjSgOdLaI6F3B0y)v%s#pXlUiQfNcK8H5E2A+x(u$rZnWkThPeMbJ7G4C1z-wt!qYmVjRgOdL9I6F3B0y(v%s#oXl