[数学]运动分析解析法作业gai.ppt

3-14 There are two assembly modes for this dyad. The first line of the subroutine is:  SUB RRP (M, YB, LAB, YA, VAY, AAY,  QAB, W, E) sin?AB=(YB-YA)/LAB cos?AB =M*SQR(1- sin?AB ^2) ?AB =ANGLE(cos?AB, sin?AB) 将 sin?AB =(YB-YA)/LAB 对时间求导，可求出?: cos?AB *?= - VAY /LAB ?= -VAY /(LAB* cos?AB) 再次对时间求导，可求出? SUB RRP (M, YB, LAB, YA, VAY, AAY,  QAB, W, E)  --------- END Ex.3-5 In the six-bar mechanism, the crank AB rotates at a constant speed 10rad/sec. Analyse the output motion of point F. （1）在杆AB中，Call LINK 求B（2）对杆2和杆3，Call RRR 求?DC（3）在杆DE中，Call LINK 求E（4）对杆5和杆6， Call RRP 求?EF（5）在杆5中， Call LINK 求F FOR I=0 TO 360 STEP 1 CALL LINK(0, 0, 0, 0, 0, 0, I*PI/180, 10, 0, 150,  XB, YB, VBX, VBY, ABX, ABY) CALL RRR(450, 0, 0, 0, 0, 0, XB, YB, VBX, VBY, ABX, ABY, 350, 400, QDC, W3, E3, QBC, W2, E2)  CALL LINK(450, 0, 0, 0, 0, 0, QDC-PI/6, W3, E3, 150,  XE, YE, VEX, VEY, AEX, AEY)  CALL RRP(1, 0, 400, YE, VEY, AEY, QEF, W5, E5) CALL LINK(XE, YE, VEX, VEY, AEX, AEY, QEF, W5,  E5, 400, XF, YF, VFX, VFY, AFX, AFY) PRINT I, XF, YF, VFX, VFY, AFX, AFYNEXT IEND 以下正确： CALL RRR(450, 0, 0, 0, 0, 0, XB, YB, VBX, VBY, ABX, ABY, 350, 400, QDC, W3, E3, QBC, W2, E2) 以下错误：CALL RRR(XB, YB, VBX, VBY, ABX, ABY, 450, 0, 0, 0, 0,  0, 400, 350, QBC, W2, E2, QDC, W3, E3) SUB RRP (M, YB, LAB, YA, VAY, AAY, QAB, W, E) CALL RRP(1, 0, 400, YE, VEY, AEY, QEF, W5, E5)以下常见错误：CALL RRP(0, 0, 400, YE, VEY, AEY, QEF, W5, E5) Ex3-7 . In the mechanism shown below, XG=YG=0, XB= - 42, YB=39, XD=10, YD=75, LBA=23mm, LGF=12mm, LFE=95mm, LEC=69mm, LDC=48mm, ?EFG=90?. Crank BA rotates at a constant speed of 10 rad/sec. The mechanism will be analyzed for the whole cycle when the driver BA rotates from 0? to 360? with a step size of ??1 =5?. FOR I=0 TO 360 STEP 2CALL LINK(- 42, 39, 0, 0, 0, 0, I*PI/1