网络安全试验TCP.pdf

学号 姓名：刘俊夫 专业：09信息安全 1: 2: 2.1:source IPaddress:02 Portnumber:80 2.2:DestinationIPaddress :2 Onwhat:HTTP 2.3:Icancreatemy owntrace,so: MyIPaddress:33 Destination IPaddress:7 3: 3.4:Sequencenumber:0 Howtoidentifies :there havea [SYN] 3.5:SequencenumberofSYNACK:0 Value ofACKnowledgement field:1 Howtodetermine :according tothe sequence numberthatclient computersendbySYN. Howtoidentifies :there havea [SYN,ACK] 3.6:Sequencenumber:1 3.7:Sequencenumberofone segments :1 sendtime:0.026477 ACK:566 Receivetime:0.053937 RTT: Sequence numberoftwo segments:566 send time:0.041737 ACK:2026 Receivetime:0.077294 RTT: Sequence numberofthreesegments :2026 send time:0.054026 ACK:3486 Receivetime:0.124085 RTT: Sequence numberoffoursegments :3486 sendtime:0.054690 ACK:4946 Receivetime:0.169118 RTT: Sequence numberoffive segments :4946 sendtime:0.077405 ACK:6406 Receivetime:0.217299 RTT: Sequence numberofsixsegments :6406 sendtime:0.078157 ACK:7866 Receivetime:0.267802 RTT: Difference :the send time isnt same, and the difference of ACK number based on the length of data,soit ismust bedifferently. 3.8;Length ofone segments :565 Lengthof twosegments :1460 Lengthof three segments :1460 Lengthof foursegments:1460 Lengthof five segments:1460 Lengthof sixsegments :1460 3.9:the minimum amountof availablebuffer space :6780. Lack of receiver buffer space will not ever throttle the sender,because once the receiver take awaythe datapackets ,itwill send message tothe sendertosend datapacketsagain. 3.10:therearent,because those sequence numberswere didnt the same. 3.11:Howmuchdata :164091; Yes,I can,because theACKwill decide the sequence numberthateveryreceiver. 3.12:throughput=28993.55bytes/s Sum oftime=