- 1、本文档共77页,可阅读全部内容。
- 2、有哪些信誉好的足球投注网站(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
- 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载。
- 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
查看更多
化学反应工程Chapter 5
Mixed Flow Reactor 化 学 反 应 工 程 SOLUTION Let A = PH3, R =P4 , S = H2. Then the reaction becomes 4A R + 6S with The volume of plug flow reactor is given by Eq.20 Evaluating the individual terms in this expression gives FA0 = 40 mol/hr 化 学 反 应 工 程 = hence the volume of reactor k = 10/ hr 化 学 反 应 工 程 EXAMPLE 5.6 TEST OF A KINETIC EQUATION IN A PLUG FLOW REACTOR We suspect that the gas reaction between A, B, and R is an elementary reversible reaction A + B R and we plan to test this with experiments in an isothermal plug flow reactor. Develop the isothermal performance equation for these kinetics for a feed of A, B, and inerts. (b) Show how to test this equation for an equimolar feed of A and B. 化 学 反 应 工 程 SOLUTION Feed pf A, B, and inerts. For this elementary reaction the rate is At constant pressure, basing expansion and conversion on substance A, Let M = CB0/CA0 , M′= CR0/CA0, we obtain 化 学 反 应 工 程 Hence, the design equation for plug flow, Eq.17, becomes In this expression accounts for the stoichiometry and for inerts present in the feed. (b) Equimolar feed of A and B. For CA0 =CB0 , CR0 = 0, and no inerts, we have M=1, M′= 0, εA= -0.5; hence the expression for part a reduces to 化 学 反 应 工 程 EXAMPLE 5.2 KINETICS FROM A MIXED FLOW REACTOR Pure gaseous reactant A (CA0 = 100 millimol/ liter) is fed at a steady rate into a mixed flow reactor (V = 0.1 liter) where it dimerizes (2A R). For different gas feed rates the following data are obtained: Run number 1 2 3 4 10.0 3.0 1.2 0.5 millimol/liter 85.7 66.7 50 33.4 Find a rate equation for this reaction. 化 学 反 应 工 程 SOLUTION For this stoichiometry, 2A R, the expansion factor is and the corresponding relation between concentration and conversion is or 化 学 反 应 工 程 The conversion for each run is then calculated and tabulated in column 4 of
文档评论(0)