简单的商品库存管理程序 c语言（Simple commodity inventory management program c language）.docVIP

简单的商品库存管理程序 c语言（Simple commodity inventory management program c language） # includes stdio.h # includes malloc.h # define len sizeof (struct goods) struct goods { long number. char name [20]; int count; struct goods * next; }; struct goods * creat (struct goods * head); struct goods * destory (struct goods * head); struct goods * sell (long number, int count, struct goods * head); struct goods * stock (long number, int count, struct goods * head); void list (struct goods * head); struct goods * (struct goods * p1, struct goods * head); void main () { struct goods * head = null; long number. int count, choose; i give { printf (1. shu ru sang pin xin xi \ n2. xiao shou \ n3. chao zhao \ n4. you ju sang pin xin xi \ n5. qin chu his, you sang pin \ n6. exit \ n \ n ); printf (input choose: \ n); scanf (% d choose). if (choose = = 1) head = creat (head); else if (choose = = 2) { printf (input number and count: \ n); scanf (% 7d% d number count). head = sell (number, count, head). } else if (choose = = 3) { printf (input number and count: \ n); scanf (% 7d% d number count). head = stock (number, count, head). } else if (choose = = 4) list (head); else if (choose = = 5) head = destory (head); } while (i choose! = 6); } struct goods * creat (struct goods * head1) { struct goods * head = null, * p1 * p2; int n = 0; if (head1) destory (head1); p2 = p1 = (struct goods *) malloc (len); printf (input number name: \ n); scanf (% 7d% s p2 - number, p2 - name); p2 - count = 0; while (p2 - number) { if (n = = 0) head = p1. else p1 - next = p2. p1 = p2. p2 = (struct goods *) malloc (len); printf (input number name: \ n); scanf (% 7d% s p2 - number, p2 - name); p2 - count = 0; n + +; } p1 - next = null; return head; } struct goods * destory (struct goods * head) { char word; struct goods * p1 * p2; p1 = p2 = head; i give { getchar (); printf (do you really want to destory the goods system y / n \ n?) ; scanf (% c, word); }（单词）！= Y 字！= n）； if(word==y) { 如果（P1） 做