乐亭高平中学临时用电方案设计.doc

乐亭高平中学工程 丄临时用电施工方案】 施 工 方 案 编制人：审核人： 编制人： 审核人：批准人： 编制单位: 编制时间: TOC \o 1-5 \h \z HYPERLINK \h \z 3、 建立安全检测制度 18 4、 建立电气维修制度 18 5、 建立工程拆除制度 18 6、 建立安全检查和评估制度 18 7、 建立安全用电责任制 18 8、 建立安全教育和培训制度 18 HYPERLINK = 0.7,tg(I) = 1.02 Pjs = KxXPe = 0.3 X 30= 9.0kW Qjs = PjsXtg* =9.0X1.02 =9.2kvar 钢筋弯曲机(4台) Kx = 0.3,Cos e = 0.7,tg 4) = 1.02 Pjs = KxXPe = 0.3 X 22=6.6kW Qjs = PjsXtg4)=6.6X1.02 =6.7kvar 钢筋调直机(2台) Kx 二 0.3,Cos? 二 0.7,tg4 = 1.02 Pjs = KxXPe = 0.3X15 二4.5kW Qjs = Pjs X tg 4) = 4.5 X 1.02 =4.6kvar 木工圆盘锯(8台) Kx二0.3, Cos 4)=0.9, tg =0.48 Pjs=0.3X24=7.2kW Qjs=Pjs Xtg 4)=7.2 X 0.48=3.5kvar ⑹电焊机(4台) Kx = 0.5,Cos ? = 0.4,tg = 1.984 将Jc =50%统一换算到J二100%的额定容量 Pn = Sn X Cos(p = 40kW Pjs = Kx X Pe = 0.5 X (0.5/1J/2 X40= 14.1kW Qjs = PjsXtg4)= 14.1 XI.984 =28.0kvar 砂浆搅拌机(2台) Kx = 0.5,Cos G = 0.55,tg e = 1.52 Pjs = KxXPe = 0.5 X 6.0=3.OkW Qjs = PjsXtg* =3.() X 1.52 = 6.0kvar 平板振动机(3台) Kx = 0.5,Cos ? = 0.7,tg = 1.02 Pjs = KxXPe = 0.5 X 10.5 =5.3kW Qjs 二 Pjs X tg = 5.3 X 1.02 = 5.4kvar 插入式振动机(4台) Kx = 0.5,Cos ? = 0.7,tg ①=1.02 Pjs = KxXPe = 0.5 X 12= 6.0kW Qjs = PjsXtg4)二 6.0X 1.02 二 6」kvar 潜污水泵(4台) Kx二0.5, Cos =0.8, tg4)=0.75 Pjs=0.5X28=14kW Qjs=PjsX tg 4)=14X0.75=10.5kvar 空压机(4台) Kx = 0.5,Cos ? = 0.7,tg ? = 1.02 Pjs = KxXPe = 0.5X22= llkW Qjs = PjsXtgb = 11X1.02 = 11.2kvar 蛙式打夯机(2台) Kx = 0.5 Cos ? = ().55 tg ? = 1.52 Pjs = 0.5X4 = 2kW Qjs 二 PjsX tg(l)=2Xl.52 =3.0 kvar 电动弯管机(2台) Kx=0.3, Cos =0.6, tg=1.33 Pjs=0.3X2=1.2kW Qjs=Pjs X tg 4)=1.2 X 1.33= 1.6kvar 630电渣压力焊机(1台) Kx = 0.5 Cos ? = 0.45 tg ? = 1.984 将Jc =50%统一换算到Jcl =100%的额定容量 Pn = Sn XCosl)= 13.5kW Pe= nX (Jc/Jc l)l/2XPn =1X (0.5/1 )1/2X 38.5= 27.2kW Pjs= KxX Pe 二0.5 X 27.5 二 5.5kW Qjs= PjsX tg(I)=5.5X 1.984 =10.9kvar 钢筋套丝机(4台) Kx = 0.3,Cos = 0.7,tg(I)= 1.02 Pjs = KxXPe = 0.3X16 =4.8kW Qjs 二 PjsXtg =4.8X1.02 =4.9kvar SS100/100物料提升机(4台) Kx = 0.3 Cos(p = 0.7 tg(p = 1.02 Pjs = KxX LPe = 0.3X60= 18 kW Qjs= PjsX tg(p= 18x1.02=1 4kvar 砂轮切割机、电锤、砂轮切割机、自控远红外干机。 X Pe=17.5kw 取 Kx二0.8、 cos a =0.82 即 tg a =0.7 Pj7=0.8X17.5=14KW