C语言实验报告英文版.pdfVIP

Exercise 1 #include stdio.h void main() { char c[6]; // Define an array to store the five characters entered char c1, c2, c3, c4, c5; // Five variables for storing results // A bool value used to determine if the input characters are all English letters (1 is true 0 is false) int pd = 1; printf(Input the values of c1~c5:); // Input characters scanf(%c,%c,%c,%c,%c, c[1], c[2], c[3], c[4], c[5]); // The for loop iterates through each character of the input for (int i = 1; i = 5; i++) { // Determine if the character entered is upper or lower case, if not then pd=0 if (c[i] A || (c[i] Z c[i] a) || c[i]z) { pd = 0; break; } } if (pd == 0) { // If this variable is 0, then the characters entered are not all English letters printf(The input is invalid. ); // Prompt for input error in this case } else { // If the input values are all English letters, the ASCII value of each element of the array is added by 4 and assigned to the corresponding variable c1 = c[1] + 4; c2 = c[2] + 4; c3 = c[3] + 4; c4 = c[4] + 4; c5 = c[5] + 4; // Formatting the output corresponding variables printf(The values after the encryption is: %c %c %c %c %c, c1, c2, c3, c4, c5); } } Case1: The input value is five English letters. Case2 ：The input value is not five English letters. Exercise 2 #include stdio.h void main() { double x,y; // Define the variable x and the result y printf(Please input the factor x ); scanf(%lf, x); // Input variable x // Identify the interval where x is located and perform the corresponding y operation if(x1) { y = x; }