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北京市西城区2023—2024学年度第二学期期末试卷
七年级数学答案及评分参考
2024.7
一、选择题（共16分，每题2分）
题号
1
2
3
4
5
6
7
8
答案
B
B
A
D
B
D
C
C
二、填空题（共16分，每题2分）
9.
.
10.
.
11.答案不唯一，如
??,
14.（3，x6）1.
如3果两个角是对顶角，那么这3两个角相等
13.8.
?
?y?3.
3
.90°＋α.
2
16.3，n≥3.
12.
三、解答题（共68分，第17题8分，第18题11分，第19-21题，每题9分，第22题5
15
分，第23题9分，第24题8分）
17.（1）计算：8??3?4?23
.
解：＝2?3?2?23································································································3分
3
＝-3.··················································································································4分
（2）解：由(x?1)?16，
可得x?1?4或x?1??4，
2
所以x?5或x??3.···························································································8分
?2?3?3，①
x
y
18.（1）?
②
解：①×2-②，得-5y＝10.
?4
x?y??
4.
y＝-2.····················································································3分
将y＝-2代入①中，得x??.··············································································4分
3
所以，这个方程组的解是
2
···········································································5分
?
?x??
?
3，
②
?3x?2
?
≥
x
，
①
2
?
?y??2.
（2）
解?：解不等?式①，得x≥1.·······················································································6分
x
83x
?1?
.
?
?4
解不等式②，得x＜3.·······················································································8分
4
所以这个不等式组的解集是1≤x＜3，它的整数解是1，2.·······························11分
北京市西城区2023—2024学年度第二学期期末试卷七年级数学答案及评分参考第1页（共4页）
19.解：（1）①画图如图1；·······································································································3分
图1
图2
②＜，垂线段最短.····························································································5分
（2）证明：∵∠CDF＝∠A，
∴AB∥HF（同位角相等，两直线平行）（填推理的依据）．
∴∠BDF＝∠ABD（两直线平行，内错角相等）（填推理的依据）．
∵∠BDF＋∠BEG＝180°，
∴∠ABD＋∠BEG＝180°．
∴BD∥EH．
∴∠BDF＝∠H（两直线平行，同位角相等）（填推理的依据）．
···························································································
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