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苏州市2024~2025学年第一学期学业质量阳光指标调研卷
高三物理参考答案及评分标准2025.01
一、单项选择题:共11题,每题4分,共44分.每题只有一个选项最符合题意.
题号1234567891011
答案DDCADCBCAAB
二、非选择题:共5题,共56分.其中第13~16题解答时请写出必要的文字说明、方程式和重要的演算
步骤,只写出最后答案的不能得分;有数值计算时,答案中必须明确写出数值和单位.
12.(15分,每小问3分)
(1)B
(2)B
(3)145(144-147均得分)
(4)3.3(3.2~3.5均得分)
(5)电池电动势发生了变化、内阻发生了变化、铜片和锌片插入位置或深度改变了(回答合理即得分)
13.(6分)
(1)据题意,折射角为45°·····························································1分
由折射定律得
·················································································1分
所以该玻璃的折射率··························································1分
(2)AC的距离·································································1分
光在玻璃中的传播速度··························································1分
所以光由A到C的传播时间········································1分
14.(8分)
(1)以C为研究对象,受力分析如图,货车匀速行驶时
FAcos30°+FBcos30°=mg··························································1分
FA=FB·······································································································································1分
解得·········································································1分
(2)当汽车刹车C恰好脱离B时,=0····································1分
竖直方向cos30°=mg··························································1分
水平方向sin30°=ma··························································1分
解得
即汽车刹车的最大加速度a=···········································2分
15.(12分)
(1)从B滑上A到第一次达到共同速度v1,根据系统动量守恒
·······················································2分
得·······························································1分
(2)从第一次碰撞后到第二次达到共同速
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